Consider the problem of maximizing cx subject to !
j ajx2
j ≤ b, where
each aj > 0 and b > 0, and xj is any real number. (a) Solve the problem by
applying KKT conditions. (b) Solve the Lagrangean dual. Show that there is
no duality gap, and that the optimal dual solution u is identical to the vector
μ of Lagrange multipliers that satisfies the KKT conditions. Hint: For part
(a), note that g(x) is convex.
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