Consider the piecewise defined function w(t) modeling the rate at which sand enters a container, and the differentiable function G(t) modeling the rate at which sand leaves the container. Both...


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Consider the piecewise defined function w(t) modeling the rate at which sand enters a container,<br>and the differentiable function G(t) modeling the rate at which sand leaves the container. Both<br>functions are measured in L/hr and at t = 1 hour there are 500 L in the container.<br>I> 2<br>3cos( 51 – 10) + 13, 0<1<2<br>|1 4 9 12<br>G), L/hr 10 8 15 22<br>t<br>61 + 4,<br>w( t) =<br>a) Is w(t) continuous at t = 2? Is w(t) differentiable at t = 2? Justify your answer.<br>b) Use a right Riemann sum with two subintervals indicated by the chart to approximate the<br>amount of sand that has exited the container on 1sts 9. Show your process.<br>c) Is the amount of sand in the tank increasing or decreasing at t = 4. Give a reason for your<br>answer.<br>d) Using Mean Value Theorem yields the approximation for G'(2.5) . Using correct<br>units, explain the meaning of this value in the context of the question.<br>3<br>e) Evaluate Í w(t)dt. Show your process. (remember don't simplify)<br>1<br>f) Write an equation that would represent the time K when the container has 545 L of sand in it. Do<br>not solve.<br>g) Consider the function given by h'(t) = w(t) + G(t) and give the second degree Taylor polynomial<br>centered at t = 4 for h(t). It is known that h(4) = 20 and G'(4) = -9.<br>h) Write an expression for the length of w(t) from t = 0 to t = 2. Do not solve.<br>i) Find an antiderivative that could be used to evaluate į t - G

Extracted text: Consider the piecewise defined function w(t) modeling the rate at which sand enters a container, and the differentiable function G(t) modeling the rate at which sand leaves the container. Both functions are measured in L/hr and at t = 1 hour there are 500 L in the container. I> 2 3cos( 51 – 10) + 13, 0<><2 |1="" 4="" 9="" 12="" g),="" l/hr="" 10="" 8="" 15="" 22="" t="" 61="" +="" 4,="" w(="" t)="a)" is="" w(t)="" continuous="" at="" t="2?" is="" w(t)="" differentiable="" at="" t="2?" justify="" your="" answer.="" b)="" use="" a="" right="" riemann="" sum="" with="" two="" subintervals="" indicated="" by="" the="" chart="" to="" approximate="" the="" amount="" of="" sand="" that="" has="" exited="" the="" container="" on="" 1sts="" 9.="" show="" your="" process.="" c)="" is="" the="" amount="" of="" sand="" in="" the="" tank="" increasing="" or="" decreasing="" at="" t="4." give="" a="" reason="" for="" your="" answer.="" d)="" using="" mean="" value="" theorem="" yields="" the="" approximation="" for="" g'(2.5)="" .="" using="" correct="" units,="" explain="" the="" meaning="" of="" this="" value="" in="" the="" context="" of="" the="" question.="" 3="" e)="" evaluate="" í="" w(t)dt.="" show="" your="" process.="" (remember="" don't="" simplify)="" 1="" f)="" write="" an="" equation="" that="" would="" represent="" the="" time="" k="" when="" the="" container="" has="" 545="" l="" of="" sand="" in="" it.="" do="" not="" solve.="" g)="" consider="" the="" function="" given="" by="" h'(t)="w(t)" +="" g(t)="" and="" give="" the="" second="" degree="" taylor="" polynomial="" centered="" at="" t="4" for="" h(t).="" it="" is="" known="" that="" h(4)="20" and="" g'(4)="-9." h)="" write="" an="" expression="" for="" the="" length="" of="" w(t)="" from="" t="0" to="" t="2." do="" not="" solve.="" i)="" find="" an="" antiderivative="" that="" could="" be="" used="" to="" evaluate="" į="" t="" -="" g"(t)dt.="">

Jun 04, 2022
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