Consider the following two tables where Grades.ID is a foreign key to Students.ID. Students (ID, Name) Grades(ID, Course_No, Grade) Consider the following relational algebra expressions: Exp1 := TtID,...



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Consider the following two tables where Grades.ID is a foreign key to Students.ID.<br>Students (ID, Name)<br>Grades(ID, Course_No, Grade)<br>Consider the following relational algebra expressions:<br>Exp1 := TtID, Name (Students ¤ Grades)<br>Exp2 := TStudents.ID, Name (Students x Grades)<br>In the following questions, select whether each query is equivalent to Exp1, Exp2, or<br>Neither.<br>

Extracted text: Consider the following two tables where Grades.ID is a foreign key to Students.ID. Students (ID, Name) Grades(ID, Course_No, Grade) Consider the following relational algebra expressions: Exp1 := TtID, Name (Students ¤ Grades) Exp2 := TStudents.ID, Name (Students x Grades) In the following questions, select whether each query is equivalent to Exp1, Exp2, or Neither.
SELECT DISTINCT ID, Name FROM Students NATURAL JOIN Grades;<br>Exp1<br>Exp2<br>Neither<br>

Extracted text: SELECT DISTINCT ID, Name FROM Students NATURAL JOIN Grades; Exp1 Exp2 Neither

Jun 07, 2022
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