Consider the following feedback control system. The plant transfer function is: 1 as+b P(s) = Consider a controller C(s) The desired closed-loop poles are at p1 = s2+3s+1 cs+d -30, P2.3 = -3±j4. (a)...


Which is the correct characteristic equation for the problem provided?


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Consider the following feedback control system. The plant transfer function is:<br>1<br>as+b<br>P(s) =<br>Consider a controller C(s)<br>The desired closed-loop poles are at p1 =<br>s2+3s+1<br>cs+d<br>-30, P2.3 = -3±j4.<br>(a) What is the expression of the actual closed-loop characteristic equation obtained based on P(s) and<br>C(s)?<br>(b) What is the expression of the desired closed-loop characteristic equation obtained based on the<br>desired closed-loop pole locations pį and p2,3?<br>(c) What are the values of a, b, c, and d such that the closed-loop poles are at the desired locations?<br>R(s)<br>C(s)<br>P(s)<br>Y(s)<br>Controller<br>Plant<br>

Extracted text: Consider the following feedback control system. The plant transfer function is: 1 as+b P(s) = Consider a controller C(s) The desired closed-loop poles are at p1 = s2+3s+1 cs+d -30, P2.3 = -3±j4. (a) What is the expression of the actual closed-loop characteristic equation obtained based on P(s) and C(s)? (b) What is the expression of the desired closed-loop characteristic equation obtained based on the desired closed-loop pole locations pį and p2,3? (c) What are the values of a, b, c, and d such that the closed-loop poles are at the desired locations? R(s) C(s) P(s) Y(s) Controller Plant
acccading to given. pole location.. ch<br>(8 +30) ( 8+3 +j4) (8+3-) 9).<br>A: (8+30j (8+3) ² + 4 27 =0<br>(8+ 30) 82+9+ 68+16.)=0<br>(8+36) [82+ c8+25]=0<br>83+68? +958+308? +1&8+ 750 = o.<br>83 +3682+ 2058 + 750 =o<br>b) poles are given as<br>P1=-30<br>P2,3=-3 + j4<br>characteristic equation will be<br>(s + 30) (s + (3 – 4j)) (s + (3 + 4j))=0<br>(s + 30) (s + 6s + 16)=0<br>53 + 36s2 + 196s + 480=0<br>

Extracted text: acccading to given. pole location.. ch (8 +30) ( 8+3 +j4) (8+3-) 9). A: (8+30j (8+3) ² + 4 27 =0 (8+ 30) 82+9+ 68+16.)=0 (8+36) [82+ c8+25]=0 83+68? +958+308? +1&8+ 750 = o. 83 +3682+ 2058 + 750 =o b) poles are given as P1=-30 P2,3=-3 + j4 characteristic equation will be (s + 30) (s + (3 – 4j)) (s + (3 + 4j))=0 (s + 30) (s + 6s + 16)=0 53 + 36s2 + 196s + 480=0

Jun 11, 2022
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