Consider the data. X; 3 12 20 14 Yi 55 35 60 10 25 The estimated regression equation for these data is ŷ = 70 – 3x. %D (a) Compute SSE, SST, and SSR using equations SSE = E(y; - ŷ;)², SST = E(y; -...


Consider the data.<br>X;<br>3<br>12<br>20<br>14<br>Yi<br>55<br>35<br>60<br>10<br>25<br>The estimated regression equation for these data is ŷ = 70 – 3x.<br>%D<br>(a) Compute SSE, SST, and SSR using equations SSE = E(y; - ŷ;)², SST = E(y; - y)², and SSR =<br>E(9; - 7)².<br>SSE =<br>SST =<br>SSR =<br>(b) Compute the coefficient of determination r. (Round your answer to three decimal places.)<br>,2 =<br>%D<br>Comment on the goodness of fit. (For purposes of this exercise, consider a proportion large if it is at least 0.55.)<br>The least squares line did not provide a good fit as a small proportion of the variability in y has been explained by the least squares<br>line.<br>The least squares line provided a good fit as a large proportion of the variability in y has been explained by the least squares line.<br>The least squares line provided a good fit as a small proportion of the variability in y has been explained by the least squares line.<br>The least squares line did not provide a good fit as a large proportion of the variability in y has been explained by the least squares<br>line.<br>(c) Compute the sample correlation coefficient. (Round your answer to three decimal places.)<br>Need Help?<br>Read It<br>

Extracted text: Consider the data. X; 3 12 20 14 Yi 55 35 60 10 25 The estimated regression equation for these data is ŷ = 70 – 3x. %D (a) Compute SSE, SST, and SSR using equations SSE = E(y; - ŷ;)², SST = E(y; - y)², and SSR = E(9; - 7)². SSE = SST = SSR = (b) Compute the coefficient of determination r. (Round your answer to three decimal places.) ,2 = %D Comment on the goodness of fit. (For purposes of this exercise, consider a proportion large if it is at least 0.55.) The least squares line did not provide a good fit as a small proportion of the variability in y has been explained by the least squares line. The least squares line provided a good fit as a large proportion of the variability in y has been explained by the least squares line. The least squares line provided a good fit as a small proportion of the variability in y has been explained by the least squares line. The least squares line did not provide a good fit as a large proportion of the variability in y has been explained by the least squares line. (c) Compute the sample correlation coefficient. (Round your answer to three decimal places.) Need Help? Read It

Jun 01, 2022
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