Consider the data. 3. 12 14 55 35 60 10 25 The estimated regression equation for these data is ŷ = 70 – 3x. (a) Compute SSE, SST, and SSR using equations SSE = E(y; - ŷ;)?, sST = E(y; - y)?, and SSR =...


Consider the data.<br>3.<br>12<br>14<br>55<br>35<br>60<br>10<br>25<br>The estimated regression equation for these data is ŷ = 70 – 3x.<br>(a)<br>Compute SSE, SST, and SSR using equations SSE =<br>E(y; - ŷ;)?, sST = E(y; - y)?, and SSR =<br>SSE =<br>110<br>SST =<br>SSR =<br>170<br>(b) Compute the coefficient of determination r. (Round your answer to three decimal places.)<br>= .930<br>Comment on the goodness of fit. (For purposes of this exercise, consider a proportion large if it is at least 0.55.)<br>The least squares line did not provide a good fit as a small proportion of the variability in y has been explained by the least squares<br>line.<br>The least squares line provided a good fit as a large proportion of the variability in y has been explained by the least squares line.<br>The least squares line provided a good fit as a small proportion of the variability in y has been explained by the least squares line.<br>The least squares line did not provide a good fit as a large proportion of the variability in y has been explained by the least squares<br>line.<br>(c)<br>Compute the sample correlation coefficient. (Round your answer to three decimal places.)<br>.965<br>20<br>

Extracted text: Consider the data. 3. 12 14 55 35 60 10 25 The estimated regression equation for these data is ŷ = 70 – 3x. (a) Compute SSE, SST, and SSR using equations SSE = E(y; - ŷ;)?, sST = E(y; - y)?, and SSR = SSE = 110 SST = SSR = 170 (b) Compute the coefficient of determination r. (Round your answer to three decimal places.) = .930 Comment on the goodness of fit. (For purposes of this exercise, consider a proportion large if it is at least 0.55.) The least squares line did not provide a good fit as a small proportion of the variability in y has been explained by the least squares line. The least squares line provided a good fit as a large proportion of the variability in y has been explained by the least squares line. The least squares line provided a good fit as a small proportion of the variability in y has been explained by the least squares line. The least squares line did not provide a good fit as a large proportion of the variability in y has been explained by the least squares line. (c) Compute the sample correlation coefficient. (Round your answer to three decimal places.) .965 20

Jun 01, 2022
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