Consider an object moving along a line with the following velocity and initial position. v(t) = 6 – 3t on [0,4]; s(0) = 0 Determine the position function for t20 using both the antiderivative method...

Extracted text: Consider an object moving along a line with the following velocity and initial position. v(t) = 6 – 3t on [0,4]; s(0) = 0 Determine the position function for t20 using both the antiderivative method and the Fundamental Theorem of Calculus. Check for agreement between the two methods. O B. The position function is the antiderivative of the velocity function. O C. The position function is the derivative of the velocity function. O D. The position function is the absolute value of the antiderivative of the velocity function. Which equation below will correctly give the position function according to the Fundamental Theorem of Calculus? O A. s(t) = v(t)dt OB. s(t) = s(0) + v(t)dt a a t C. s(0) = s(t) + | v(x)dx s() = s(0) + vx)dx 0. Determine the position function for t20 using both methods. Select the correct choice below and fill in the answer box(es) to complete your choice. O A. The same function is obtained using each method. The position function is s(t) = O B. Different functions are obtained using each method. The position function obtained using the antiderivative method is s(t) = and the position function obtained using the Fundamental Theorem of Calculus is s(t) =.