Consider a word-addressable computer with 32 bits per word. The instruction set consists of 30 different instructions. All instructions have an operation code field, a mode field to specify one of 7...

Consider a word-addressable computer with 32 bits per word. The instruction set consists of 30 different instructions. All instructions have an operation code field, a mode field to specify one of 7 possible addressing modes, a register address field to specify one of 60 available registers, and a memory address field. Each instruction is stored in one word of memory. What is the maximum allowable size for memory? Use KB, MB, or GB as a unit.
Instruction size = 32bit , allow instruction = 30 add bit = 5

Registere = 60 add bit = 8
Modes = 7 add bit = 3
Then: 5+8+3+address field = 32 so address filed = 16bits
Now maximum allowable size for memory = 2 ^16 * 4 bytes = 256bKB