CONDITIONING AND EVIDENCEFred is answering a multiple-choice problem on an exam, and has to choose one of n options (exactly one of which is correct). Let K be the event that he knows the answer, and...

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CONDITIONING AND EVIDENCEFred is answering a multiple-choice problem on an exam, and has to choose one of n options (exactly one of which is correct). Let K be the event that he knows the answer, and R be the event that he gets the problem right (either through knowledge or through luck). Suppose that if he knows the right answer he will de?nitely get the problem right, but if he does not know then he will guess completely randomly. Let P(K) = p. (a) Find P(K|R) (in terms of p and n). (b) Show that P(K|R) = p, and explain why this makes sense intuitively. When (if ever) does P(K|R) equal p?

Answered Same DayDec 26, 2021

Answer To: CONDITIONING AND EVIDENCEFred is answering a multiple-choice problem on an exam, and has to choose...

David answered on Dec 26 2021
122 Votes
a) There are total of n options so in case of guess (G),
P(R|G) = 1/n
P(Rc| G) = 1 – 1/n
We ne
ed to find P(K| R) i.e. probability that Fred knows the answer given that he answered it right.
Now,
( | )
( )
( )

P(K and R) = P(R | K)*P(K) = 1*p = p
And
P(R) = P(R |...
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