Compute and print out a table of the function Y = 1/(4 – x?) in the range 0

can anybody do it?Compute and print out a table of the function Y = 1/(4 – x?)<br>in the range 0 <X<2 using a variable step interval. Start out<br>with a step width of 0.1 (i.e. X = 0,0.1, 0.2.1.9). Reduce the<br>step width by a factor of 10 whenever X would reach 2<br>during next iteration, or whenever two successive values<br>differ by more than 10. Stop the tabulation when Y reaches<br>100.<br>Details of printout: The x and Y values are to be<br>printed in two parallel columns, in the 2nd and 4th field.<br>Headings are to be printed as shown below. An extra blank<br>line is to be inserted whenever the step interval is changed.<br>FUNCTION TABLE OF F (X) = 1/(4 -X**2)<br>2 blank lines - {<br>VALUE OF X<br>VALUE OF F(X)<br>2 blank lines {<br>0•00000E + 00<br>2-50000E – 01<br>

Extracted text: Compute and print out a table of the function Y = 1/(4 – x?) in the range 0 <><2 using="" a="" variable="" step="" interval.="" start="" out="" with="" a="" step="" width="" of="" 0.1="" (i.e.="" x="0,0.1," 0.2.1.9).="" reduce="" the="" step="" width="" by="" a="" factor="" of="" 10="" whenever="" x="" would="" reach="" 2="" during="" next="" iteration,="" or="" whenever="" two="" successive="" values="" differ="" by="" more="" than="" 10.="" stop="" the="" tabulation="" when="" y="" reaches="" 100.="" details="" of="" printout:="" the="" x="" and="" y="" values="" are="" to="" be="" printed="" in="" two="" parallel="" columns,="" in="" the="" 2nd="" and="" 4th="" field.="" headings="" are="" to="" be="" printed="" as="" shown="" below.="" an="" extra="" blank="" line="" is="" to="" be="" inserted="" whenever="" the="" step="" interval="" is="" changed.="" function="" table="" of="" f="" (x)="1/(4" -x**2)="" 2="" blank="" lines="" -="" {="" value="" of="" x="" value="" of="" f(x)="" 2="" blank="" lines="" {="" 0•00000e="" +="" 00="" 2-50000e="" –="">

Jun 10, 2022
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