complete the word doc entitled "LAB7REPORTFORM" using the data that is attached. no plagiarism is allowed and no work should be posted online after the work is completed.

complete the word doc entitled "LAB7REPORTFORM" using the data that is attached. no plagiarism is allowed and no work should be posted online after the work is completed.


·Name · · ·Group · · PLEASE ENABLE EDITING BEFORE FILLING OUT THIS REPORT! No report will be accepted for credit after that date/time. Grade: Results: (60 pts) Room Temperature Reactant Mg Mg MgO MgO Trial Number 1 2 3 4 Mass of reactant (from data) Moles of reactant (calculate) Initial time (ti) (from graph) Initial Temperature (Ti) (from the graph) Linear Curve fit slope (m) (from the graph) Linear Curve fit intercept (b) (from the graph) Final Temperature (Tf) (calculate from linear fit data) ∆T = Tf – Ti qwater qcalorimeter qrxn ∆Hrxn Use the following to determine the enthalpy of formation of magnesium oxide: Mg (s) + 2HCl (aq) → MgCl2 (aq) + H2 (g) ΔH = (calculated in the experiment) MgO (s) + 2HCl (aq) → MgCl2 (aq)+ H2O (l) ΔH = (calculated in the experiment) H2 (g) + ½O2 (g) → H2O (l) ΔH = - 285.8 kJ/mol Mg (s) + ½ O2 (g) MgO (s) ΔH = (determine using Hess’s Law) Calculations: (40 pts) ·Using the enthalpies of reaction computed in the lab and the value given for the enthalpy of formation of liquid water, show the Hess’s Law determination of the enthalpy of formation of solid magnesium oxide. Show your work. If you include a scan of your handwritten work, it must be legible. (30 pts) ·Compare the value you calculated with the actual value (-601.8 kJ/mol). Show your determination of percent error. Use the standard equation for this: (10 pts) Room Temperature (use a thermometer to 1 decimal place) A NOC If you record the data from the graph in the table below, there is no need to print the graph. Reactant Mg Mg MgO MgO Trial Number 1 2 3 4 0330S [oB3BE A Mass of reactant Goad 6 (4 decimal places) Data from graph 26.20¢|3l-loc Initial Temp (to) (4 5) Initial Time (Te) (4 59) Sos 36.505 Linear Curve fit slope (m) sh S2.55y 4-528 0” Linear Curve fit intercept (b) as = Notes: 29.9% ¢| 3465 ¢