Comparing Two Resistor Vendors A procurement specialist has purchased 25 resistors from vendor 1 and 35 resistors from vendor 2. Each resistor’s resistance is measured with the following results:...

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Comparing Two Resistor Vendors

A procurement specialist has purchased 25 resistors from vendor 1 and 35 resistors from vendor 2. Each resistor’s resistance is measured with the following results:

Vendor 1






































96.8100.0100.398.598.398.2
99.699.499.9101.1103.797.7
99.7101.197.798.6101.9101.0
99.499.899.199.6101.298.2
98.6



Vendor 2


















































106.8106.8104.7104.7108.0102.2
103.2103.7106.8105.1104.0106.2
102.6100.3104.0107.0104.3105.8
104.0106.3102.2102.8104.2103.4
104.6103.5106.3109.2107.2105.4
106.4106.8104.1107.7107.7


Questions:

  1. Prepare two simple frequency distribution tables one for each vendor

  2. Calculate the mean for each vendor.

  3. Do the vendors have the same variability?

  4. Comment on the graph of resistor 1





  1. Comment on the graph of resistor 2





  1. Compute the Confidence Interval (CI) for both resistors using an Alpha of 5%. What added information the CI brings? Compare both vendors based on the CI calculations.



  1. Based on the previous calculations: Standard of Deviations, Means, and CI’s, Which vendor would you recommend to the procurement specialist? Substantiate your answers.




Comparing Two Resistor Vendors A procurement specialist has purchased 25 resistors from vendor 1 and 35 resistors from vendor 2. Each resistor’s resistance is measured with the following results: Vendor 1 96.8 100.0 100.3 98.5 98.3 98.2 99.6 99.4 99.9 101.1 103.7 97.7 99.7 101.1 97.7 98.6 101.9 101.0 99.4 99.8 99.1 99.6 101.2 98.2 98.6 Vendor 2 106.8 106.8 104.7 104.7 108.0 102.2 103.2 103.7 106.8 105.1 104.0 106.2 102.6 100.3 104.0 107.0 104.3 105.8 104.0 106.3 102.2 102.8 104.2 103.4 104.6 103.5 106.3 109.2 107.2 105.4 106.4 106.8 104.1 107.7 107.7 Questions: 1- Prepare two simple frequency distribution tables one for each vendor 2- Calculate the mean for each vendor. 3- Do the vendors have the same variability? 4- Comment on the graph of resistor 1 5- Comment on the graph of resistor 2 6- Compute the Confidence Interval (CI) for both resistors using an Alpha of 5%. What added information the CI brings? Compare both vendors based on the CI calculations. 7- Based on the previous calculations: Standard of Deviations, Means, and CI’s, Which vendor would you recommend to the procurement specialist? Substantiate your answers. 96.899.699.799.498.610099.4101.199.8100.399.997.799.198.5101.198.699.698.3103.7101.9101.298.297.710198.2106.8103.2102.6104104.6106.4106.8103.7100.3106.3103.5106.8104.7106.8104102.2106.3104.1104.7105.1107102.8109.2107.7108104104.3104.2107.2107.7102.2106.2105.8103.4105.4
Answered Same DayDec 21, 2021

Answer To: Comparing Two Resistor Vendors A procurement specialist has purchased 25 resistors from vendor 1 and...

David answered on Dec 21 2021
116 Votes
Question 1
Frequency distribution for vendor 1:
Resistance Frequency
96.8 1
97.7 2

98.2 2
98.3 1
98.5 1
98.6 1
98.6 1
99.1 1
99.4 2
99.6 2
99.7 1
99.8 1
99.9 1
100 1
100.3 1
101 1
101.1 2
101.2 1
101.9 1
103.7 1
Frequency distribution for vendor 2:
Resistance Frequency
100.3 1
102.2 2
102.6 1
102.8 1
103.2 1
103.4 1
103.5 1
103.7 1
104 3
104.1 1
104.2 1
104.3 1
104.6 1
104.7 2
105.1 1
105.4 1
105.8 1
106.2 1
106.3 2
106.4 1
106.8 4
107 1
107.2 1
107.7 2
108 1
109.2 1
Question 2
Mean for vendor 1 = 2489.4/25 = 99.576
Mean for vendor 2: = 3678/35 = 105.0857
Question 3
We calculate the standard deviation by the following formula:
σx -
2
]
Variance is square of the standard deviation.
Variance for vendor 1 = 2.34
Variance for vendor 2 = 3.934
(you can use the standard deviation formula in excel and then square the results to obtain the
variance)...
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