Company XYZ know that replacement times for the DVD players it produces are normally distributed with a mean of 8.5 years and a standard deviation of 1.6 years. If the company wants to provide a...


Company XYZ know that replacement times for the DVD<br>players it produces are normally distributed with a mean of<br>8.5 years and a standard deviation of 1.6 years.<br>If the company wants to provide a warranty so that only<br>1.3% of the DVD players will be replaced before the<br>warranty expires, what is the time length of the warranty?<br>warranty =<br>years<br>%3D<br>Enter your answer as a number accurate to 1 decimal<br>place. Answers obtained using exact z-scores or z-scores<br>rounded to 3 decimal places are accepted.<br>796<br>

Extracted text: Company XYZ know that replacement times for the DVD players it produces are normally distributed with a mean of 8.5 years and a standard deviation of 1.6 years. If the company wants to provide a warranty so that only 1.3% of the DVD players will be replaced before the warranty expires, what is the time length of the warranty? warranty = years %3D Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. 796

Jun 01, 2022
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