Coarse aggregate is placed in a rigid bucket (mold) and rodded with a tamping rod to determine its unit weight. The following data were obtained: Volume of bucket ½ ft Weight of empty bucket = 20.3...


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Coarse aggregate is placed in a rigid bucket (mold) and rodded with a tamping rod to determine<br>its unit weight. The following data were obtained:<br>Volume of bucket ½ ft<br>Weight of empty bucket = 20.3 lb.<br>Weight of bucket filled with dry-rodded coarse aggregate = 69.6 lb.<br>3.<br>%3D<br>Calculate the dry-rodded unit weight, and if the bulk specific gravity of the aggregate is 2.620,<br>calculate the pereent voids between the aggregate particles. Assume the unit weight of water =<br>62.4 lb/ ft.<br>

Extracted text: Coarse aggregate is placed in a rigid bucket (mold) and rodded with a tamping rod to determine its unit weight. The following data were obtained: Volume of bucket ½ ft Weight of empty bucket = 20.3 lb. Weight of bucket filled with dry-rodded coarse aggregate = 69.6 lb. 3. %3D Calculate the dry-rodded unit weight, and if the bulk specific gravity of the aggregate is 2.620, calculate the pereent voids between the aggregate particles. Assume the unit weight of water = 62.4 lb/ ft.

Jun 11, 2022
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