Pls solve fast and correct do not solve wrong
Extracted text: Coarse aggregate is placed in a rigid bucket (mold) and rodded with a tamping rod to determine its unit weight. The following data were obtained: Volume of bucket ½ ft Weight of empty bucket = 20.3 lb. Weight of bucket filled with dry-rodded coarse aggregate = 69.6 lb. 3. %3D Calculate the dry-rodded unit weight, and if the bulk specific gravity of the aggregate is 2.620, calculate the pereent voids between the aggregate particles. Assume the unit weight of water = 62.4 lb/ ft.