Chronic Illness - A recent survey asked a large sample of U.S. adults about their health. The report from the survey calculated that (0.41, 0.48) is a 90% confidence interval for the proportion of...

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Extracted text: Chronic Illness - A recent survey asked a large sample of U.S. adults about their health. The report from the survey calculated that (0.41, 0.48) is a 90% confidence interval for the proportion of U.S. adults who say they "live with one or more chronic conditions." Round all answers to four decimal places. 1. Use the reported confidence interval to find the sample proportion, p, used to calculate the confidence interval. 2. Use the reported confidence interval to find the margin of error for the interval. ME = 0.035 3. Use the reported confidence interval to find the standard error for the interval. SE; 0.0213 4. Use the sample proportion and the standard error to calculate a 95% confidence interval using the same survey data.