Chem. 132 Homework Problems Fall 2019 Chemistry: Homework Problems: You Need to Master. Chapter 16 Chemical Equilibrium This homework requires you toAnswer all the questions and turn in your answers...

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Chem. 132 Homework Problems Fall 2019


Chemistry: Homework Problems: You Need to Master.


Chapter 16 Chemical Equilibrium


This homework requires you toAnswer all the questions and turn in your answers last day of class on Friday December 6, 2019


1) Give the direction of the reaction, if K >> 1.


2) Give the direction of the reaction, if K


3) Give the direction of the reaction, if K ≈ 1.


4) Express the equilibrium constant for the following reaction. CH4(g) + 2 O2(g)⇔CO2(g) + 2 H2O(g)


5) The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant.


H2(g) + Br2(g)⇌HBr(g) Kc= 3.8 × 104HBr(g)⇌H2(g) + Br2(g) Kc= ?


6) The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant.


H2(g) + Br2(g)⇌2 HBr(g) Kc= 3.8 × 1044 HBr(g)⇌2 H2(g) + 2 Br2(g) Kc= ?


7) The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant.


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Chem. 132 Homework Problems


Fall 2019


2 SO2(g) + O2(g)⇌2 SO3(g) SO3(g)⇌1/2 O2(g) + SO2(g)


Kc= 1.7 × 106Kc= ?


8) The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant.


A(g) + B(g)⇌AB(g) AB(g) + A(g)⇌A2B(g) 2 A(g) + B(g)⇌A2B(g)


Kc = 0.24 Kc= 3.8 Kc= ?


9) The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant.


A(g) + 2 B(g)⇌AB2(g) AB2(g) + B(g)⇌AB3(g) A(g) + 3 B(g)⇌AB3(g)


Kc = 59 Kc= ? Kc= 478


10) The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant.


2 A(g) + B(g)⇌A2B(g) A2B(g) + B(g)⇌A2B2(g) 2 A(g) + 2 B(g)⇌A2B2(g)


Kc = ? Kc= 16.4 Kc= 28.2


10) Express the equilibrium constant for the following reaction. Pb(NO3)2(aq) + 2 NaI(aq)⇌PbI2(s) + 2 NaNO3(aq)


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Chem. 132 Homework Problems Fall 2019


12) Express the equilibrium constant for the following reaction. 4 Al(s) + 3 O2(g)⇌2 Al2O3(s)


13) Determine the value of Kcfor the following reaction if the equilibrium concentrations are as follows: [P4O10]eq= 2.000 moles, [P4]eq= 3.000 moles, [O2]eq= 4.000 M


P4O10(s)⇌P4(s) + 5 O2(g)


14) Determine the value of Kcfor the following reaction if the equilibrium concentrations are as follows: [N2]eq= 3.6 M, [O2]eq= 4.1 M, [N2O]eq= 3.3 × 10-18M.


2 N2(g) + O2(g)⇌2 N2O(g)


15) Determine the value of Kcfor the following reaction if the equilibrium concentrations are as follows: [N2]eq= 1.5 M, [H2]eq= 1.1 M, [NH3]eq= 0.47 M.


N2(g) + 3 H2(g)⇌2 NH3(g)


16) Determine the value of Kcfor the following reaction if the equilibrium concentrations are as follows: [HCl]eq= 0.13 M, [HI]eq= 5.6 × 10-16M, [Cl2]eq= 0.0019 M.


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Chem. 132 Homework Problems Fall 2019


2 HCl(g) + I2(s)⇌2 HI(g) + Cl2(g)
17) Determine the value of Kcfor the following reaction if the equilibrium concentrations are as


follows: [HCl]eq= 0.13 M, [HI]eq= 5.6 × 10-16M, [Cl2]eq= 0.0019 M. 2 HI(g) + Cl2(g)⇌2 HCl(g) + I2(s)


18) Determine the value of Kpfor the following reaction if the equilibrium concentrations are as follows: P(CO)eq= 6.8 × 10-11atm, P(O2)eq= 1.3 × 10-3atm, P(CO2)eq= 0.041 atm.


2 CO(g) + O2(g)⇌2 CO2(g)


19) In a reaction mixture containing only reactants, what is the value of Q?


20) In a reaction mixture containing only products, what is the value of Q?


21) Express the equilibrium constant for the following reaction. 4 CH3Cl(g) + 2 Cl2(g)⇔4 CH2Cl2(g) + 2 H2(g)


22) Express the reverse equilibrium constant for the following reaction. 4 CH3Cl(g) + 2 Cl2(g)⇔4 CH2Cl2(g) + 2 H2(g)


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Chem. 132 Homework Problems


Fall 2019


23) Express the equilibrium constant for the following reaction. 10 N2(g) + 30 H2(g)⇔20 NH3(g)


24) Express the equilibrium constant for the following reaction. 12 NH3(g)⇔6 N2(g) + 18 H2(g)


25) Express the equilibrium constant for the following reaction. 10 PCl5(g)⇌10 PCl3(g) + 10 Cl2(g)


26) Express the equilibrium constant for the following reaction. 8 H2(g) + 8 Br2(g)⇌16 HBr(g)


27) Express the reverse equilibrium constant for the following reaction. 8 H2(g) + 8 Br2(g)⇌16 HBr(g)


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Chem. 132 Homework Problems


Fall 2019


28) Express the equilibrium constant for the following reaction. 14 P(g) + 21 Cl2(g)⇌14 PCl3(g)


29) Express the reverse equilibrium constant for the following reaction. 4 P(g) + 6 Cl2(g)⇌4 PCl3(g)


30) Express the equilibrium constant for the following reaction. 20 CH3Br(g) + 10 Br2(g)⇔20 CH2Br2(g) + 10 H2(g)


31) The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant.


2 HD(g)⇌H2(g) + D2(g) Kc= 0.28 5 H2(g) + 5 D2(g)⇌10 HD(g) Kc= ?


32) The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant.


N2O4(g)⇌2 NO2(g) Kc= 1.46 3 N2O4(g)⇌6 NO2(g) Kc= ?


33) Phosphorous trichloride and phosphorous pentachloride equilibrate in the presence of molecular chlorine according to the reaction:


PCl3(g) + Cl2(g)⇌PCl5(g)
An equilibrium mixture at 450 K contains


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Chem. 132 Homework Problems


Fall 2019


= 0.124 atm,
= 0.157 atm, and


= 1.30 atm. What is the value of Kpat this temperature? 34) What is Δnfor the following equation in relating Kcto Kp?


N2(g) + 3 F2(g)⇌2 NF3(g)


35) What is Δn for the following equation in relating Kcto Kp? 2 NCl3(g)⇌N2(g) + 3 Cl2(g)


36) What is Δnfor the following equation in relating Kcto Kp? CH4(g) + H2O(g)⇌CO(g) + 3 H2(g)


37) What is Δn for the following equation in relating Kcto Kp? 2 SO2(g) + O2(g)⇌2 SO3(g)


38) What is Δnfor the following equation in relating Kcto Kp? 2 SO3(g)⇌2 SO2(g) + O2(g)


39) What is Δn for the following equation in relating Kcto Kp? N2O4(g)⇌2 NO2(g)


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Chem. 132 Homework Problems


Fall 2019


40) What is Δnfor the following equation in relating Kcto Kp? C3H8(g) + 5 O2(g)⇌3 CO2(g) + 4 H2O(l)


41) What is Δn for the following equation in relating Kcto Kp? 4 NH3(g) + 3 O2(g)⇌2 N2(g) + 6 H2O(g)


42) What is Δnfor the following equation in relating Kcto Kp? SO3(g) + NO(g)⇌SO2(g) + NO2(g)


43) What is△n for the following equation in relating Kcto Kp? P4(s) + 5 O2(g)⇌P4O10(s)


44) What is△n for the following equation in relating Kcto Kp? 2 Na(s) + 2 H2O(l)⇌2 NaOH(aq) + H2(g)


45) What is△n for the following equation in relating Kcto Kp? KIO3(s)⇌KIO(s) + O2(g)


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Chem. 132 Homework Problems


Fall 2019


46) Express the equilibrium constant for the following reaction. 6 Na(s) + 6 H2O(l)⇌6 NaOH(aq) + 3 H2(g)


47) Express the equilibrium constant for the following reaction. RbBrO3(s)⇌RbBrO(s) + O2(g)


48) Express the equilibrium constant for the following reaction. 2 P4(s) + 10 O2(g)⇌2 P4O10(s)


49) Express the equilibrium constant for the following reaction. 5 P4O10(s)⇌5 P4(s) + 25 O2(g)


50) Determine the value of Kcfor the following reaction if the equilibrium concentrations are as follows: [PBr5]eq= 0.56 M, [PBr3]eq= 0.23 M, [Br2]eq= 6.6 M.


PBr5(g)⇌PBr3(g) + Br2(g)


51) Determine the value of Kcfor the following reaction if the equilibrium concentrations are as follows: [H2]eq= 0.14 M, [Br2]eq= 0.39 M, [HBr]eq= 1.6 M.


H2(g) + Br2(g)⇌2 HBr(g)


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Chem. 132 Homework Problems Fall 2019


52) Determine the value of Kpfor the following reaction if the equilibrium concentrations are as follows: P(NOCl)eq= 0.22 atm, P(NO)eq= 0.10 atm, P(Cl2)eq= 0.11 atm.


2 NOCl(g)⇌2 NO(g) + Cl2(g)


53) Identify the change that will always shift the equilibrium to the right. 2 SO2(g) + O2(g)⇌2 SO3(g)


54) The following reaction is exothermic. Which change will shift the equilibrium to the left? 2 SO2(g) + O2(g)⇌2 SO3(g)


55) The equilibrium constant is equal to 5.00 at 1300 K for the reaction: 2 SO2(g) + O2(g)⇌2 SO3(g).


If initial concentrations are [SO2] = 6.00 M, [O2] = 0.45 M, and [SO3] = 9.00 M, describe the system?


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Chem. 132 Homework Problems


Fall 2019


Match the following.


A) reaction is at equilibrium
B) reaction has a larger amount of products than reactants C) reaction favors formation of more products
D) reverse reaction is favored
E) reaction will favor formation of reactants
F) reaction does not strongly favor reactants or products


1) K 2) K ≈ 13) Q < k="" 4)="" q=""> K 5) Q = K 6) Q >> 1


Matching Questions


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Answered Same DayDec 02, 2021

Answer To: Chem. 132 Homework Problems Fall 2019 Chemistry: Homework Problems: You Need to Master. Chapter 16...

Jayageetha answered on Dec 04 2021
157 Votes
Chapter 16 Chemical Equilibrium
1. Forward direction
2. Reverse direction
3. The reaction is at equilibrium
4. CH4(g) + 2 O2(g) ⇔ CO2(g) + 2 H2O(l)
K`c =         [
CO2] [H2O]2
                        ________________
                        [CH4] [O2]2    
Conc. of water     =    1 g/ mL × 1000 mL /1 L× mol /18 g
=     55 mol/L    
                    
Hence, Equilibrium Constant (Kc) = K`c *[H2O]2
5. Given : H2(g) + Br2(g) ⇌ 2 HBr(g)
Kc                 =    3.8 × 104
[HBr] / [H2] × [Br2]     =    3.8 × 104
Hence, [H2] × [Br2]/ [HBr] =     1/(3.8× 104) = 2.6e-5
6. H2(g) + Br2(g) ⇌ 2 HBr(g) Kc = 3.8 × 104
4 HBr(g) ⇌ 2 H2(g) + 2 Br2(g) Kc = ?
[HBr]2 / [H2] [Br2] = 3.8 × 104
Hence, [HBr]4/ [H2]2 [Br2]2 = (3.8 × 104)2 = 1.44 × 109
7. 2SO2(g) + O2(g) ⇌ 2 SO3(g) Kc = 1.7 × 106
SO3(g) ⇌ 1/2 O2(g) + SO2(g) Kc = ?
[SO3]2 / [SO2]2 [O2] = 1.7 × 106
Hence,
[SO2] [O2]1/2 / [SO3] = 1/ √1.7 × 106 = 7.67 e-4
8. A(g) + B(g) ⇌ AB(g)
AB(g) + A(g) ⇌ A2B(g)
On adding the above equations, we get the third equation, 2 A(g) + B(g) ⇌ A2B(g).
Hence Kc for the third equation = 0.24 + 3.8 = 4.04
9. A(g) + 2 B(g) ⇌ AB2(g) Kc = 59
AB2(g) + B(g) ⇌ AB3(g) Kc = ?
A(g) + 3 B(g) ⇌ AB3(g) Kc = 478

On adding the first two equations, we get the third equation.
A(g) + 2 B(g) + AB2(g) + B(g) ⇌ AB2(g) + AB3(g)
Hence, A(g) + 3 B(g) ⇌ AB3(g)
Therefore, Kc of the second reaction = 478 – 59 = 419
10. 2 A(g) + B(g) ⇌ A2B(g) Kc = ?
A2B(g) + B(g) ⇌ A2B2 (g) Kc = 16.4
2 A(g) + 2 B(g) ⇌ A2B2 (g) Kc = 28.2
On adding the first two equations, we get the third equation.
2 A(g) + B(g) + A2B(g) + B(g) ⇌ A2B(g) + A2B2 (g)
Hence, Kc for the first equation = 28.2 – 16.4 = 11.8
11. Pb(NO3)2(aq) + 2...
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