Chapter 10 Problems 1. A helium filled party balloon has a volume of 4.50 L at sea level, where the atmospheric pressure is 748 Torr. Assuming that the temperature remains constant, what will be the...

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Answered 2 days AfterMay 29, 2021

Answer To: Chapter 10 Problems 1. A helium filled party balloon has a volume of 4.50 L at sea level, where the...

Jatin answered on May 31 2021
147 Votes
1. Initial conditions:
P1= 748 torr
V1= 4.50 L
Final conditions:
P2= 557 torr
To find: V2
Applying Boyle’s law:
= 6.04 L
The volume of the balloon will be = 6.04 L
The p
roblem uses Boyle’s law.
2. Initial conditions:
P1= 988 torr
V1= 535 mL = 0.535 L
T1= 25˚C = 298 K
Final conditions:
V2= 1.05 L
T2= 25˚C = 298 K
To find: P2
Applying the equation:
= 503.41 torr
The gas pressure in the flask will be = 503.41 torr.
3. Initial conditions:
V1= 2.0 L
T1= 27˚C = 300 K
Final conditions:
T2= -23 ˚C = 250 K
To find: V2
Applying the Charles’s law:
= 1.67 L
The gas will occupy a volume of 1.67 L outdoors.
This problem uses Charles’s law.
4. Initial conditions:
V1= 692 L
T1= 602˚C = 875 K
Final conditions:
T2= 23 ˚C = 300 K
To find: V2
Applying the Charles’s law:
= 237.26 L
After cooling, the gas will occupy a volume of 237.26 L.
5. At STP:
Pressure(P)= 1 atm
Temperature(T)= 273 K
To find: Volume(V) occupied by methane gas
Universal gas constant(R)= 0.08206 L atm K-1 mol-1
Molar mass of methane= 12+4=16 g mol-1
Number of moles(n) of methane gas= 4.11×1000 g /16 g mol-1
= 685 moles
Applying the ideal gas equation and substituting the values:
PV= nRT
= 15345.63 L
Volume(V) occupied by methane gas is = 15345.63 L
This problem uses the Ideal gas law.
6. At STP:
Pressure(P)= 1 atm
Temperature(T)= 273 K
Given: Volume of container= 50.0 L
Universal gas constant(R)= 0.08206 L atm K-1 mol-1
Applying the ideal gas equation and substituting the values:
PV= nRT
= 2.232 mol
Mass of 1 mole of propane= (12×3) + (8×1) = 44 g
Mass of 2.232 moles of propane= 2.232× 44= 98.208 g
7. Volume of the container(V)= 15.0 L
Temperature(T) =...
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