Modular Stars Modular Stars Due Monday by 11:59pm Points 100 Submitting a file upload File Types pdf Submit Assignment Complete the following activities: 1. It was mentioned in the lesson material...

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Answered Same DayDec 11, 2021

Answer To: Modular Stars Modular Stars Due Monday by 11:59pm Points 100 Submitting a file upload File Types pdf...

Rajeswari answered on Dec 13 2021
160 Votes
48900 Assignment
Qno.1
For 6 points,if we connect alternate points we get 1,3,5 and 1. So 2 , 4 an
d 6 are left out. If we leave 2 and connect like 1 to 4 and 4 to 7 mod6 we get only one line connecting 1 and 4 and hence there are other vertices left out. If we leave 4 at a time we connect 1 to 5 then 5 to 9 mod 6 i.e. 3, 3 to 7 mod 6 again 1. Hence here also only 3 vertices can be connected. Connecting 1 to 6 is nothing than the side of the polygon. Hence there cannot be a continuous star connecting all the lines when 6 points are there.
This is because except 5 all other numbers are factors of 6. We cannot select 5 because we join adjoint vertices.
Question no.2
For an even number of points, always 2 is a divisor. ...
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