Can you explain to me why the teta is 63.43, how did the solution come up with it please break it down for me in words as well as the solutions in pin a to pin c thank youu I really needed help understanding it
![& MG:°] Re (40) - foocG0) - 800(30)~1000(20)+ bo0(20) = 0<br>t fy- o] RetR6= 400+8 004100<br>Rc (40) : 56000<br>40 Re = SUO00<br>1900<br>Re: 1400 Ib<br>pin A<br>o: tan-' ()<br>AB<br>fry> o] AB sin (6343) - 100 = 0<br>AB = 441. 25 1b] T<br>63,43°<br>AU<br>€ Fx =01 Ac+ 447.23 cos (63.43) - o<br>400 Ib<br>AC : - 200 Ib<br>rin B<br>£ Fy: 0] - BC sin (6343) - 447. 23 sin l6a.ta) = D<br>BU = -441.233 1b/c<br>Çoolb<br>BD<br>& fx - 07 60+ 600 H-+41-233)(03(6 3.43) - 447-233 cos (63149) - 0<br>441-23 ib<br>BC<br>3D= -20016 C<br>Pin u<br>- 447.23 1b<br>eD<br>Fg -07 1400 + co sin C63.43) - 447-23 sin (63. 43) - 0<br>cp = - 118-08 i6<br>-2001<br>CE<br>し<br>140016<br>](https://s3.us-east-1.amazonaws.com/storage.unifolks.com/qimg-008/008_vlcbzp0-fso5gj40.png)
Extracted text: & MG:°] Re (40) - foocG0) - 800(30)~1000(20)+ bo0(20) = 0 t fy- o] RetR6= 400+8 004100 Rc (40) : 56000 40 Re = SUO00 1900 Re: 1400 Ib pin A o: tan-' () AB fry> o] AB sin (6343) - 100 = 0 AB = 441. 25 1b] T 63,43° AU € Fx =01 Ac+ 447.23 cos (63.43) - o 400 Ib AC : - 200 Ib rin B £ Fy: 0] - BC sin (6343) - 447. 23 sin l6a.ta) = D BU = -441.233 1b/c Çoolb BD & fx - 07 60+ 600 H-+41-233)(03(6 3.43) - 447-233 cos (63149) - 0 441-23 ib BC 3D= -20016 C Pin u - 447.23 1b eD Fg -07 1400 + co sin C63.43) - 447-23 sin (63. 43) - 0 cp = - 118-08 i6 -2001 CE し 140016
Extracted text: 800 lb 600 lb 20 A 20 20 20- 400 lb 1000 lb