Calculate the plane stresses involved where two pieces of steel are welded together. Our sign convention defines forces causing the object to be in tension positive and forces causing the object to be in compression negative. As we can see from the picture our
σx = −4.5MPa and σy = 10MPa. Steel has an average Young’s modulus of elasticity of E = 200 GPa and an average Poisson’s ratio of ν = .285 Because it is not defined we will assume that initially there is no shear stress, τxy = 0.
Solve only for: Compression in the x-direction(deformation along the weld)=(-Blank 4)? x 10^-5
Extracted text: Calculate the plane stresses involved where two pieces of steel are welded together. Our sign convention defines forces causing the object to be in tension positive and forces causing the object to be in compression negative. As we can see from the picture our ox = -4.5MPA and oy = 10MPA. Steel has an average Young's modulus of elasticity of E = 200 GPa and an average Poisson's ratio of v = .285 Because it is not defined we will assume that initially there is no shear stress, Txy = 0. 10 MPå What kind of ... stresses ? 100 mm -250 mm- 4.5 MPa Weld ez00r BrockalCole,a tivaiona Thomeon Leaming, he. Thoman Laaming ia Yadenark ned hern uncer en Stress in the x direction - Blank 1 Stress in y direction ,=Blank 2 Shear Stress on the weld 7= Blank 3 Compression in the x-direction(deformation along the weld)=-Blank 4 x 10^-5