Calculate the global warming time. This is the time interval from the original steady state (Problem 9.6) to the new steady state (Problem 9.7), during which the average temperature of Earth increases by ΔT = 0.28 K. During the same time interval, the Earth area-averaged excess solar heat flux that is absorbed by the Earth surface is q′′ = 0.85 W∕m2 (Problem 9.7). Assume that the thermal inertia of the “Earth surface” is dominated by the thermal inertia of the oceans and the ocean depth averaged over the entire Earth is on the order of 1 km.
Problem 9.7
Read the preceding problem statement and consider the impact of a sudden change in the radiative properties of the atmosphere. The albedo increases from 𝜌1= 0.3 to 𝜌2= 0.3 + 𝛽, where 𝛽 ≪ 0.3, and the greenhouse factor increases from 𝛾1= 0.4 to 𝛾2= 0.4 + 𝜀, where 𝜀 ≪ 0.4. The Earth surface temperature does not have time to change: It is still at the level T1= 288.7 K calculated in the preceding problem by using 𝜌1and 𝛾1. This creates an imbalance between the solar heat input qs2(associated with 𝜌2) and the rejected heat current q∞2= 4𝜋R2(1 − 𝛾2)𝛼T41. Measurements show that the heat input imbalance is (qs2− q∞2)∕(4𝜋R2) = 0.85 W∕m2. Find what relation must exist between 𝛽 and 𝜀 such that this heat current imbalance occurs. If enough time passes, the Earth surface temperature rises to a new steady-state level T2such that the rejected heat current matches the solar input qs2. Show that the final global warming effect is T2− T1≅ 0.3 K.
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