c) What value does your test statistic,T, take on with the sample data? d) What type of probability distribution does your test statistic,T, have? O t O normal O Chi-Squared O binomial O Cauchy


c) What value does your test statistic,T, take on with the sample data?<br>d) What type of probability distribution does your test statistic,T, have?<br>O t<br>O normal<br>O Chi-Squared<br>O binomial<br>O Cauchy<br>

Extracted text: c) What value does your test statistic,T, take on with the sample data? d) What type of probability distribution does your test statistic,T, have? O t O normal O Chi-Squared O binomial O Cauchy
The ruby-throated hummingbird beats its wings very quicky. Using a high-speed camera, an ornithologist was able to measure the wing beating speed (in beats per second) of 14 randomly chosen ruby-throated<br>hummingbirds. The following are the measurements:<br>54.20, 51.99, 46.96, 50.91, 51.05, 45.75, 46.80, 50.57, 52.45, 48.41, 53.39, 51.97, 50.37, 51.41<br>Research has shown that wing beat speed is normally distributed. So, we assume that our sample comes from a normal population with an unknown mean of µ and an unknown standard deviation of o. . We<br>would like to test whether the average wing beat speed of ruby-throated hummingbirds is greater than 50 beats per second.<br>The null hypothesis is thus Ho:H=50 . We will test this against the alternative Ha .<br>We want to test at the 6% level.<br>Let x<br>the sample mean and s =<br>the sample standard deviation.<br>a) What should the alternative hypothesis, Ha , be?<br>O Hail=6%<br>Ο Ha μ50<br>О наи+50<br>Ο H μ=50<br>O HaiH<50<br>b) What is the formula for your test statistic?<br>OT =<br>x -6%<br>х-50<br>OT =<br>13<br>х-50<br>OT =<br>13<br>x-50<br>OT =<br>14<br>x-50<br>OT =<br>S<br>14<br>

Extracted text: The ruby-throated hummingbird beats its wings very quicky. Using a high-speed camera, an ornithologist was able to measure the wing beating speed (in beats per second) of 14 randomly chosen ruby-throated hummingbirds. The following are the measurements: 54.20, 51.99, 46.96, 50.91, 51.05, 45.75, 46.80, 50.57, 52.45, 48.41, 53.39, 51.97, 50.37, 51.41 Research has shown that wing beat speed is normally distributed. So, we assume that our sample comes from a normal population with an unknown mean of µ and an unknown standard deviation of o. . We would like to test whether the average wing beat speed of ruby-throated hummingbirds is greater than 50 beats per second. The null hypothesis is thus Ho:H=50 . We will test this against the alternative Ha . We want to test at the 6% level. Let x the sample mean and s = the sample standard deviation. a) What should the alternative hypothesis, Ha , be? O Hail=6% Ο Ha μ50 О наи+50 Ο H μ=50 O HaiH<50 b)="" what="" is="" the="" formula="" for="" your="" test="" statistic?="" ot="x" -6%="" х-50="" ot="13" х-50="" ot="13" x-50="" ot="14" x-50="" ot="S">

Jun 09, 2022
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