C++ programming language Please help me. If possible can the code be as simple as possible please? so i can understand. > optinal)The sum of The product of two complex numbers is given by...

C++ programming language

Please help me. If possible can the code be as simple as possible please? so i can understand.

Extracted text: Classes and operator overloading Define a class for complex numbers. A complex number is a number of the form: a + b*i where for purposes, and b are numbers of type our a double and i is a number that represents the quantity v-1 (i * i = -1). Represent a complex number two values of type double. Name the as member variables real and imaginary. (The variable for the number that is multiplied by i is the called imaginary.) Call the class one Complex. Include a constructor with two parameters of type double that can be used to set the member variables of an object to any values. Include constructor that has only a single parameter of type a double ; call this parameter realPart and define the constructor so that the object will be initialized to realPart + 0*i . Include a default constructor that initializes an object to 0 (that is, to 0 + 0*i). Overload all the following operators so that they correctly apply to the type Complex: +, -, *, «, (>> optinal) The sum of The product of two complex numbers is given by the following formula: (a + b*i)+(c + d*i) = (a+c)+ (b+d) *i The difference of The product of two complex numbers is given by the following formula: (а + b*i)-(с+d*i) %3 (а-с)+ (b-d) *i The product of two complex numbers is given by the following formula: (a + b*i)* (c + d*i) = (a*c b*d) + (a*d + b*c) *i You should also write a test program: Instantiate four complex numbers C1=(1+4*i), C2=(-3-7i), C3= (4*i)and C4= (-3+ i) Add, subtract and multiply Cl and C2. Add, subtract and multiply C3 and C4. Use the overloaded « to display the result of the three operations as follow:


Extracted text: 7*i) 7*i) |(1 + 4*i) + (-3 |(1 + 4*i) |(1 + 4*i) * (-3 - 7*i) (4*i) + (-3 + i) (4*i) |(4*i) -2 3*i %3D (-3 4 + 11*i - %3D 25 19*i -3 + 5*i %3D (-3 + i) (-3 + i) 3 + 3*i = -4 12*i %3D || ||