C programming I'm trying to fix memory leak but it kept giving that one error. Where did I go wrong? #include #include void printArray(int *arr, int size){ int i; if (arr != NULL) { for( i = 0; i

C programming I'm trying to fix memory leak but it kept giving that one error. Where did I go wrong?

#include
#include

void printArray(int *arr, int size){
   int i;
   if (arr != NULL)
   {
   for( i = 0; i < size;="" i++)="">
       // Print each element out
       printf("%d", *(arr+i));
       //Print addresses of each element
       printf("%p", (arr+i));
       //Printing a new line
       printf("\n");
   }
}
}

int main() {

   // Allows user to specify the original array size, stored in variable n1.
   printf("Enter original array size: ");
   int n1 = 0;
   scanf("%d", &n1);
   //a- Create a new array *a1 of n1 ints using malloc
   int *a1 = malloc(n1 * sizeof(int));
   //b- Remove comments for if statment below
   //b- Set each element in a1 to 100 + indexValue ??
   if(a1 == NULL)
{
printf("Error! memory not allocated.");
   exit(0);
}
   int i;
   for (i = 0; i < n1;="">
   {
       a1[i] = 100 + i;
   }

   printf("Printing the first array allocated using malloc\n");
   //c- Print each element and addresses out (to make sure things look right)
   printArray(a1, n1);

   // User specifies the new array size, stored in variable n2.
   printf("\nEnter new array size: ");
   int n2 = 0;
   scanf("%d", &n2);
   //d- Dynamically change the array a1 to size n2
   a1 = malloc (n2 * sizeof(int));

   //e- Remove comments for if statment below
   if(a1 == NULL)
   {
   printf("Error! memory not allocated.");
   exit(0);
   }


   //e- If the new array is a larger size, set all new members to 200 + indexValue.
   if (n2 > n1)
   {
       int i;
       for (i = 0; i < n2;="">
       {
           a1[i] = 100 + i;
       }
   }

   printf("Printing the reallocated array: \n");
   //f- Print each element and addresses out (to make sure things look right)
   printArray(a1, n2);

   //g-Free the allocated memory for a1
   free(a1);
   a1 = NULL;

   printf("\nEnter new array size to be initialized with 0: ");
   int n3 = 0;
   scanf("%d", &n3);
   //h- Remove comments for if statement
   //h- Using calloc create a new array and assign it to a2
   //with new array size, stored in variable n3.
   int *a2 =calloc(n3, sizeof(int));

if(a2 == NULL)
{
   printf("Error! memory not allocated.");
   exit(0);
   }

   printf("Printing the array created using calloc: \n");
   //i- Print array a2 with size n3
   printArray(a2, n3);

   //j- Print array a1 again, How you can fix this problem
   printf("Printing deallocated array a1: \n");
   printArray(a1, n2);

   // Done with arrays now, free the and assign NULL

   free(a2);
   a1 = NULL;
   a2 = NULL;

   printf("Program Successfully Completed!");
   return 0;
}

Extracted text: Printing deallocated array al: Program Successfully Completed!==83051== ==83051== HEAP SUMMARY: in use at exit: 40 bytes in 1 blocks total heap usage: 3 allocs, 2 frees, 240 bytes allocated ==83051== ==83051== ==83051== ==83051== 40 bytes in 1 blocks are definitely lost in loss record 1 of 1 ==83051== at 0×4C29F73: malloc (vg replace malloc.c:309) by 0x400815: main (dynamic.c:29) ==83051== ==83051== ==83051== LEAK SUMMARY: ==83051== definitely lost: 40 bytes in 1 blocks indirectly lost: 0 bytes in 0 blocks possibly lost: 0 bytes in 0 blocks still reachable: 0 bytes in 0 blocks suppressed: 0 bytes in 0 blocks ==83051== ==83051== ==83051== Activate Windows ==83051== ==83051== Go to Settings to activate ==83051== For lists of detected and suppressed errors, ==83051== ERROR SUMMARY: 1 errors from 1 contexts (suppressed: 0 from 0) rerun Wiheows.