(c) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. PP • The value of the test statistic is given by p(1-p) • The p-value is two times the area under the...


Answer the following questions on first and second picture and show your solution.


(c) Perform a Z-test and find the p-value.<br>Here is some information to help you with your Z-test.<br>PP<br>• The value of the test statistic is given by<br>p(1-p)<br>• The p-value is two times the area under the curve to the right of the value of the test statistic.<br>Standard Normal Distribution<br>Step 1: Select one-tailed or two-tailed.<br>O One-tailed<br>O Two-tailed<br>03+<br>Step 2: Enter the test statistic.<br>(Round to 3 decimal places.)<br>02<br>Step 3: Shade the area represented by<br>the p-value.<br>0.1-<br>Step 4: Enter the p-value,<br>(Round to 3 decimal places.)<br>2.<br>(d) Based on your answer to part (c), choose what can be concluded, at the 0.05 level of significance, about the claim<br>made in the school's reports.<br>O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is<br>enough evidence to reject the claim that 44% of students will find a match their first time using the site.<br>O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is<br>not enough evidence to reject the claim that 44% of students will find a match their first time using the site.<br>O Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough<br>evidence to reject the claim that 44% of students will find a match their first time using the site.<br>O Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough<br>evidence to reject the claim that 44% of students will find a match their first time using the site.<br>

Extracted text: (c) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. PP • The value of the test statistic is given by p(1-p) • The p-value is two times the area under the curve to the right of the value of the test statistic. Standard Normal Distribution Step 1: Select one-tailed or two-tailed. O One-tailed O Two-tailed 03+ Step 2: Enter the test statistic. (Round to 3 decimal places.) 02 Step 3: Shade the area represented by the p-value. 0.1- Step 4: Enter the p-value, (Round to 3 decimal places.) 2. (d) Based on your answer to part (c), choose what can be concluded, at the 0.05 level of significance, about the claim made in the school's reports. O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 44% of students will find a match their first time using the site. O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 44% of students will find a match their first time using the site. O Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that 44% of students will find a match their first time using the site. O Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that 44% of students will find a match their first time using the site.
1<br>3.<br>6<br>8<br>9.<br>10<br>At a nearby college, there is a school-sponsored website that matches people looking for roommates. According to the school's reports, 44% of students will find<br>a match their first time using the site. A writer for the school newspaper tests this claim by choosing a random sample of 160 students who visited the site<br>looking for a roommate. Of the students surveyed, 77 said they found a match their first time using the site.<br>Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to reject the claim that the<br>proportion, P, of all students who will find a match their first time using the site is 44%.<br>(a) State the null hypothesis H, and the alternative hypothesis H, that you would use for the test.<br>H: 0<br>OSO<br>H,: 0<br>D=0<br>ロロ<br>(b) For your hypothesis test, you will use a Z-test. Find the values of np and n(1-p) to confirm that a Z-test can be used. (One standard is that np 2 10<br>and n(1-p) 2> 10 under the assumption that the null hypothesis is true.) Here n is the sample size and p is the population proportion you are testing.<br>np=0<br>n(1-p) =0<br>

Extracted text: 1 3. 6 8 9. 10 At a nearby college, there is a school-sponsored website that matches people looking for roommates. According to the school's reports, 44% of students will find a match their first time using the site. A writer for the school newspaper tests this claim by choosing a random sample of 160 students who visited the site looking for a roommate. Of the students surveyed, 77 said they found a match their first time using the site. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to reject the claim that the proportion, P, of all students who will find a match their first time using the site is 44%. (a) State the null hypothesis H, and the alternative hypothesis H, that you would use for the test. H: 0 OSO H,: 0 D=0 ロロ (b) For your hypothesis test, you will use a Z-test. Find the values of np and n(1-p) to confirm that a Z-test can be used. (One standard is that np 2 10 and n(1-p) 2> 10 under the assumption that the null hypothesis is true.) Here n is the sample size and p is the population proportion you are testing. np=0 n(1-p) =0
Jun 08, 2022
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