(C Language) Topic: Pointers 2Instructions:3 int main(void) {int n;printf("Enter the destination number: ");scanf("%d", &n);41. In the code editor, you are provided with a main()code that asks...



(C Language) Topic: Pointers


main.c<br>Please help me by pointing me to the correct address.<br>1 #include<stdio.h><br>2<br>Instructions:<br>3 int main(void) {<br>int n;<br>printf(

Extracted text: main.c Please help me by pointing me to the correct address. 1 #include 2 Instructions: 3 int main(void) { int n; printf("Enter the destination number: "); scanf("%d", &n); 4 1. In the code editor, you are provided with a main() code that asks for an integer input from the user and stores this to the variable n. 2. Your task is to set the value of the destination_ptr found at line 9 to the address of the variable n. 7 // TODO: Assign the address of n to this pointer int *destination_ptr; 8. 10 3. Aside from this, do not edit anything else. 11 12 if(*destination_ptr == n) { printf("Found it!"); } else { printf("Hmm, something's not right"); } 13 Input 14 15 1. An integer value 16 17 18 Output 19 return 0; 20 }. Enter the destination number: 2 Found it!
main.c<br>< ><br>+<br>Instructions:<br>1 #include<stdio.h><br>2<br>1. In the code editor, there are three things present:<br>1. An integer value representing the next<br>3 int main(void) {<br>int next_destination = 10;<br>4<br>destination<br>5<br>2. Pointer #1 which represents the first signage<br>int *pointer_1, *pointer_2;<br>6<br>3. And Pointer #2 which represents the second<br>signage<br>7<br>8<br>// TODO: Perform instruction 2.a<br>2. For this problem, you need to do two things:<br>1. Assign the address of the integer value (or the<br>next_destination) to Pointer #2<br>10<br>11<br>// TODO: Perform instruction 2.b<br>12<br>2. Assign the value of Pointer #2 to Pointer #1<br>3. Using Pointer #1 and the dereferencing<br>13<br>14<br>// TODO: Perform instruction 2.c<br>operator, print the value of the<br>15<br>next destination<br>16<br>17<br>return 0;<br>18 }.<br>Output<br>Next destination = 20<br>

Extracted text: main.c <> + Instructions: 1 #include 2 1. In the code editor, there are three things present: 1. An integer value representing the next 3 int main(void) { int next_destination = 10; 4 destination 5 2. Pointer #1 which represents the first signage int *pointer_1, *pointer_2; 6 3. And Pointer #2 which represents the second signage 7 8 // TODO: Perform instruction 2.a 2. For this problem, you need to do two things: 1. Assign the address of the integer value (or the next_destination) to Pointer #2 10 11 // TODO: Perform instruction 2.b 12 2. Assign the value of Pointer #2 to Pointer #1 3. Using Pointer #1 and the dereferencing 13 14 // TODO: Perform instruction 2.c operator, print the value of the 15 next destination 16 17 return 0; 18 }. Output Next destination = 20
Jun 04, 2022
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