C++ int lastof(const int a[], int aLen, const int b[], int bLen){int pos = -1;for (size t i = 0; i [3, 2, 11, 10, 1]b1->[8, 10, 6]last0f (al, 5, b1, 3): -1Expected: 3al->[3, 2, 11, 10,...

C++

Extracted text: Write the function lastOf which searches the array a for the last occurance of any value contained in the array b. Returns the index if found. If not found, return -1. arrays.cpp 1 #include int lastof(const int a[], int aLen, const int b[], int bLen) { int pos = -1; for (size t i = 0; i < alen;="" ++i)="" if="" (a[i]="" return="" pos;="" 3="" 4="" 5="" 6="" 7="=" pos)="" pos="i;" 8="" 10="" 11="" }="" codecheck="" reset="" testers="" running="" tester.cpp="" fail="" pass="" fail="" fail="" fail="" al-="">[3, 2, 11, 10, 1] b1->[8, 10, 6] last0f (al, 5, b1, 3): -1 Expected: 3 al->[3, 2, 11, 10, 1] b2->[5, 6] last0f(al, 5, b2, 2): -1 Expected: -1 а2->[4, 12, 12, 10, 12, 1, 5, 10, 11, 9, 8] b2->[5, 6] last0f (a2, 11, b2, 2): -1 Expected: 6 а2->[4, 12, 12, 10, 12, 1, 5, 10, 11, 9, 8] b1->[8, 10, 6] lastof (a2, 11, b1, 3): -1 Expected: 10 а2->[4, 12, 12, 10, 12, 1, 5, 10, 11, 9, 8] b3->[11, 2, 1, 15] lastof (a2, 11, b3, 4): -1 Expected: 8 Score 1/5