By the method of separation of variables, the solution of the dimesionless boundary value problem expressed in terms of the dimensionless Nusselt number Nu = hL/k is %3D 0(X, Y) EOn(X,Y) %3D n=1 E Cn...

By the method of separation of variables, the solution of the dimesionless<br>boundary value problem expressed in terms of the dimensionless Nusselt<br>number Nu = hL/k is<br>%3D<br>0(X, Y)<br>EOn(X,Y)<br>%3D<br>n=1<br>E Cn sinh (nnX) sin (nnY)<br>n=1<br>where<br>2Nu<br>(а) Сп —<br>1-(-1)

Extracted text: By the method of separation of variables, the solution of the dimesionless boundary value problem expressed in terms of the dimensionless Nusselt number Nu = hL/k is %3D 0(X, Y) EOn(X,Y) %3D n=1 E Cn sinh (nnX) sin (nnY) n=1 where 2Nu (а) Сп — 1-(-1)" пп сosh (пт) Nu (b) Сп — 1- (-1)" sinh (n7) Nu (с) Сп 3 1- (-1)" cosh (nn) 2Nu (d) Cn = 1 – (-1)" NA sinh (nn) | 2Nu (e) Cn = 1- (-1)" NT cosh (nr) + Nu sinh (nn) ||

Jun 05, 2022

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By the method of separation of variables, the solution of the dimesionless boundary value problem expressed in terms of the dimensionless Nusselt number Nu = hL/k is %3D 0(X, Y) EOn(X,Y) %3D n=1 E Cn...

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