Build a hash table using chaining as the collision resolution technique. Insertions into the hash table will correspond to declarations of variables and values in a program, searches will be requests...

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Build a hash table using chaining as the collision resolution technique. Insertions into the hash


table will correspond to declarations of variables and values in a program, searches will be


requests for the value of a variable. Some variables will be local and have a narrow scope while


some variables will be global.


The program will take input from a file, another program written in the omnipotent programming


language BORG (Bionicly Omnipotent Resistance Grinders) and generate output from this


program.


The BORG language has the following commands (keywords):


1. START-FINISH blocks. Indicating different scopes.


2. COM - Single line comments: Text should be ignored if on the same line


3. VAR varName – Variable Declaration, adds “varName” to the hash table.


4. variable = expression – Assignment statements, ie GEORGE = 122. Find GEORGE in


the hash table and assign 122 to it.


5. ++ - increment operator, syntax: VARIABLE ++


6. -- - decrement operator, syntax: VARIABLE --


7. expressions, expressions are limited to unary and binary arithmetic, or variable names


8. supported operators: + - / * % ^ (plus, minus, divide, multiple, modulo, exponent)


9. PRINT – syntax PRINT expression. If the expression is a variable, and this variable is not


in scope, then an error message indicating unknown variable x at line number y. The


value printed if there is a variable in scope should be the variable with the closest scope.


10. Errors – other than the print statements, our interpreter will not be responsible for


detecting errors, syntax errors should be disregarded if encountered, assume that the


source file is correct.


Our hash function: sum the ordinal values of the characters of the variable multiplied by their


position in the string (1-indexing), then taking the modulo by TABLESIZE.


ie. The variable ABC = (65 * 1 + 66 * 2 + 67 * 3) % TABLESIZE


All tokens are separated by one space or a new line.


Output:


for this assignment, run your interpreter on this sample source program as well as a


program of your own

Answered Same DayMay 15, 2021

Answer To: Build a hash table using chaining as the collision resolution technique. Insertions into the hash...

Pritam answered on May 19 2021
149 Votes
public class CS41Assignment4 { static int TABLESIZE = 37; /*Intialize an array size of 37*/ static int Hashing(String chars) { int hash = 0; for (int i = 0; i < chars.length(); i++) { hash += chars.charAt(i) * (i + 1); } return hash % TABLESIZE; /* return the index in the hash table */ } public static void main(String[]...
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