Student Instructions BM Overview - Benchmark Your group has been given a dataset containing 240 records, located in the Student_BM tab of this spreadsheet.. Each student is only responsible for...

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Benchmark - Ethical Behavior of Business Students at Bo Diddley Tech





Student Instructions BM Overview - Benchmark Your group has been given a dataset containing 240 records, located in the Student_BM tab of this spreadsheet.. Each student is only responsible for analyzing 60 of these record records - the specifics of which will be assigned by the instructor. It is important that each student has a unique 60 records, as the results will be an input into the CLC, and duplication of results is not helpful. Note that the data have been randomized, so the data given to your group are likely different than the data given to other groups. The intent of this assignment is for students to organize their data using a pivot table, get a graphical understanding of the data through a bar chart, then do hypothesis testing comparing Bo Diddly Tech results versus the national average. All of your analysis should be done in the Student_BM tab of this spreadsheet and submitted as part of the assignmemt. The location where the pivot table, bar chart, and relevant information should be placed in the Student_BM tab is indicated by RED instructions. Once completed, the Student_BM tab will serve as the basis for writing your management report. It is expected that any conclusions you draw in the management report will be consistent with the data and analyses contained in the spreadsheet. Instructions Data Analysis Component: 1. Make a pivot table with: Business Student (Rows), Athlete (Rows), Cheated (Columns), and Cheated (Summed Value). 2. Create a bar chart showing cheating by athletes and business students. 4. Determine if there is a statistical difference between nonathlete BDT business students and the national average for business students as reported by the Chronicle of Higher Education. 5. Determine if there is a statistical difference between athlete BDT business students and the national average for business students as reported by the Chronicle of Higher Education. 6. Determine if there is a statistical difference between BDT business students and the national average for business students as reported by the Chronicle of Higher Education. 7. Determine if there is a statistical difference between BDT nonbusiness students and the national average for nonbusiness students as reported by the Chronicle of Higher Education. Instructions Data Interpretation Component: Utilizing the data you have analyzed, write a managerial report of 500-800 words to the dean. The managerial report needs to include an introduction, analysis, conclusion, and a minimum of three supporting references. 1. Introduction (Define): Explain in your own words why you are providing this report and the problem(s) you are trying to solve. 2. Collect: Describe the data set you used. 3. Organize: Describe your pivot table. 4. Visualize: Include and describe your bar chart. 5. Analyze: Provide a summary of your conclusions based upon the four population proportion hypothesis tests. 6. The Dean has expressed a concern related to the amount of cheating currently taking place at Bo Diddley Tech and has strongly suggested that you “tweak” the statistical data such that it favors the image of the university. Discuss the potential use of unethical manipulation of statistical data to provide a biased outcome as well as the ethical counter proposal you would offer the dean in this scenario. 7. Conclusion: What advice would you give to the dean based on your analysis of the data? Student_BM CollegeAthleteCheated1. Pivot TableNationwide Average% Cheated Insert pivot table in this cell - F2Business56% Nonbusiness47% 2. Bar Chart Bar chart starts in this cell - F20 Insert the appropriate numbers into the hypothesis testing calculations below based upon your pivot table results. Note the results. 3-6 Hypothesis Test Business Nonathlete vs. National AverageBusiness Athlete vs. National AverageBusiness vs. National AverageNonbusiness vs. National Average ProportionProportionProportionProportion Sample Size (n) =count(range)Sample Size (n) =count(range)Sample Size (n) =count(range)Sample Size (n) =count(range) Response of Interest (ROI)CheatedResponse of Interest (ROI)CheatedResponse of Interest (ROI)CheatedResponse of Interest (ROI)Cheated Count for Response (CFR) =COUNTIF(range,ROI)Count for Response (CFR) =COUNTIF(range,ROI)Count for Response (CFR) =COUNTIF(range,ROI)Count for Response (CFR) =COUNTIF(range,ROI) Sample Proportion (pbar) =CFR/nSample Proportion (pbar) =CFR/nSample Proportion (pbar) =CFR/nSample Proportion (pbar) =CFR/n Highlight your H0 and HaTwo Tail H0: p = po Ha: p ≠ po Left Tail H0: p ≥ po Ha: p < po="" right="" tail="" h0:="" p="" ≤="" po="" ha:="" p=""> poHighlight your H0 and HaTwo Tail H0: p = po Ha: p ≠ po Left Tail H0: p ≥ po Ha: p < po="" right="" tail="" h0:="" p="" ≤="" po="" ha:="" p=""> poHighlight your H0 and HaTwo Tail H0: p = po Ha: p ≠ po Left Tail H0: p ≥ po Ha: p < po="" right="" tail="" h0:="" p="" ≤="" po="" ha:="" p=""> poHighlight your H0 and HaTwo Tail H0: p = po Ha: p ≠ po Left Tail H0: p ≥ po Ha: p < po="" right="" tail="" h0:="" p="" ≤="" po="" ha:="" p=""> po Hypothesized0.56Hypothesized0.56Hypothesized0.56Hypothesized0.47 Confidence Coefficient (Coe)0.95Confidence Coefficient (Coe)0.95Confidence Coefficient (Coe)0.95Confidence Coefficient (Coe)0.95 Level of Significance (alpha) =1-Coe0.05Level of Significance (alpha) =1-Coe0.05Level of Significance (alpha) =1-Coe0.05Level of Significance (alpha) =1-Coe0.05 Standard Error (StdError) =SQRT(Hypo*(1-Hypo)/n)ERROR:#DIV/0!Standard Error (StdError) =SQRT(Hypo*(1-Hypo)/n)ERROR:#DIV/0!Standard Error (StdError) =SQRT(Hypo*(1-Hypo)/n)ERROR:#DIV/0!Standard Error (StdError) =SQRT(Hypo*(1-Hypo)/n)ERROR:#DIV/0! Test Statistic (Z-stat) =(pbar-Hypo)/StdErrorERROR:#DIV/0!Test Statistic (Z-stat) =(pbar-Hypo)/StdErrorERROR:#DIV/0!Test Statistic (Z-stat) =(pbar-Hypo)/StdErrorERROR:#DIV/0!Test Statistic (Z-stat) =(pbar-Hypo)/StdErrorERROR:#DIV/0! Accept or Reject: Left TailERROR:#DIV/0!Accept or Reject: Left TailERROR:#DIV/0!Accept or Reject: Left TailERROR:#DIV/0!Accept or Reject: Left TailERROR:#DIV/0! Accept or Reject: Right TailERROR:#DIV/0!Accept or Reject: Right TailERROR:#DIV/0!Accept or Reject: Right TailERROR:#DIV/0!Accept or Reject: Right TailERROR:#DIV/0! Accept or Reject: Two TailERROR:#DIV/0!Accept or Reject: Two TailERROR:#DIV/0!Accept or Reject: Two TailERROR:#DIV/0!Accept or Reject: Two TailERROR:#DIV/0! p-value (Lower Tail) =NORM.S.DIST(z,TRUE)ERROR:#DIV/0!p-value (Lower Tail) =NORM.S.DIST(z,TRUE)ERROR:#DIV/0!p-value (Lower Tail) =NORM.S.DIST(z,TRUE)ERROR:#DIV/0!p-value (Lower Tail) =NORM.S.DIST(z,TRUE)ERROR:#DIV/0! p-value (Upper Tail) =1-LowerTailERROR:#DIV/0!p-value (Upper Tail) =1-LowerTailERROR:#DIV/0!p-value (Upper Tail) =1-LowerTailERROR:#DIV/0!p-value (Upper Tail) =1-LowerTailERROR:#DIV/0! p-value (Two Tail) =2*MIN(LowerTail,UpperTail)ERROR:#DIV/0!p-value (Two Tail) =2*MIN(LowerTail,UpperTail)ERROR:#DIV/0!p-value (Two Tail) =2*MIN(LowerTail,UpperTail)ERROR:#DIV/0!p-value (Two Tail) =2*MIN(LowerTail,UpperTail)ERROR:#DIV/0! Accept or Reject p-value: Left TailERROR:#DIV/0!Accept or Reject p-value: Left TailERROR:#DIV/0!Accept or Reject p-value: Left TailERROR:#DIV/0!Accept or Reject p-value: Left TailERROR:#DIV/0! Accept or Reject p-value: Right TailERROR:#DIV/0!Accept or Reject p-value: Right TailERROR:#DIV/0!Accept or Reject p-value: Right TailERROR:#DIV/0!Accept or Reject p-value: Right TailERROR:#DIV/0! Accept or Reject p-value: Two TailERROR:#DIV/0!Accept or Reject p-value: Two TailERROR:#DIV/0!Accept or Reject p-value: Two TailERROR:#DIV/0!Accept or Reject p-value: Two TailERROR:#DIV/0! p-Lower Limit =pbar-CONFIDENCE.NORM(alpha,StdError,n)ERROR:#DIV/0!p-Lower Limit =pbar-CONFIDENCE.NORM(alpha,StdError,n)ERROR:#DIV/0!p-Lower Limit =pbar-CONFIDENCE.NORM(alpha,StdError,n)ERROR:#DIV/0!p-Lower Limit =pbar-CONFIDENCE.NORM(alpha,StdError,n)ERROR:#DIV/0! p-Upper Limit =pbar+CONFIDENCE.NORM(alpha,StdError,n)ERROR:#DIV/0!p-Upper Limit =pbar+CONFIDENCE.NORM(alpha,StdError,n)ERROR:#DIV/0!p-Upper Limit =pbar+CONFIDENCE.NORM(alpha,StdError,n)ERROR:#DIV/0!p-Upper Limit =pbar+CONFIDENCE.NORM(alpha,StdError,n)ERROR:#DIV/0!
Answered Same DayJul 18, 2021

Answer To: Student Instructions BM Overview - Benchmark Your group has been given a dataset containing 240...

Subhanbasha answered on Jul 19 2021
163 Votes
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Introduction:
    The data about the behavior of the students in the college especially about the department of Bio Diddly Tech. This
data will help us to find the how many students are doing cheating or how much percentage of the students are doing cheating in the college and they are belongs to particular group that mean they are business or non-business students and they are athletes or non- athletes. By using this sample data we can easily find the behavior of the students.
    In this analysis we are using excel spreadsheet to make the some of the insights from the data which will be useful to know the student behavior which is the main aim of this analysis. There we are going to use some graphical method and pivot tables and some of the statistical tests to test the difference between the various categories of the student with respect to the cheating.
Dataset:
    The data set contains three attributes of the students those are college that means the student belongs to Business College or non-business college, the second column is Athlete that mean the student is belonging to athlete group or non-athlete group and the last column is cheating whether the student is doing cheating or not with yes or no responses.
    The entire data in the text format only from that data we can segregate the each group behavior with the count of students. Here it will be useful to get the pivot...
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