Bases and Subspaces Worksheet Advanced Linear Algebra, Spring 2013 The vector space for this worksheet is P2; the set of polynomials of degree less that or equal to 2. We are given a basis for this...

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Answered Same DayDec 22, 2021

Answer To: Bases and Subspaces Worksheet Advanced Linear Algebra, Spring 2013 The vector space for this...

Robert answered on Dec 22 2021
124 Votes
1. Suppose v ∈ W then we can written as linear combination of spanning
element of W .
We have give
n [v]S =
 10
1
 This gives v = 1.(1 + t + t2) + 0.(1 + t) +
1(1 + t2)
v = 2 + t + 2t2
Now suppose v ∈W , there must exists a, b, c scalars, such that
2 + t + 2t2 = a(1 + 2t + 3t2) + b(2 + t) + c(1 + t + t2)
2 + t + 2t2 = (a + 2b + c) + (2a + b + c)t + (3a + c)t2
Hence we have
3a + c = 2 2a + b + c = 1 a + 2b + c = 2
We have c = 2− 3a, putting this in remaining equation we get
2a + b + 2− 3a = 1 a + 2b + 2− 3a = 2
that is we have
−a + b = −1 2b− 2a = 0
Which is absurd and do not have solution. Hence we can not find...
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