(b) A continuous single effect evaporator is to be fed with 5000 kg/hr. of solution having 1 wt% solute. The feed is at a temperature of 303K. It is to be concentrated to a solution of 2 wt% solute....


(b) A continuous single effect evaporator is to be fed with 5000 kg/hr. of solution having 1 wt%<br>solute. The feed is at a temperature of 303K. It is to be concentrated to a solution of 2 wt% solute.<br>The evaporation operating at a pressure of 101.3 kPa in the vapor space. Saturated steam is<br>supplied at 143.3 kPa for heating.<br>Calculate the weight of the vapor produced, and the weight of the steam required. Also calculate<br>the necessary heating surface.<br>[Note: The solution is so dilute that its specific heat, latent heat and boiling point may be assumed<br>to be the same as those of water]<br>h= 125.79 kJ/kg, h̟= 419.04 kJ/kg, H,=2676.1 kJ/kg, H,= 2691.5 kJ/kg, h,= 461.30 kJ/kg<br>

Extracted text: (b) A continuous single effect evaporator is to be fed with 5000 kg/hr. of solution having 1 wt% solute. The feed is at a temperature of 303K. It is to be concentrated to a solution of 2 wt% solute. The evaporation operating at a pressure of 101.3 kPa in the vapor space. Saturated steam is supplied at 143.3 kPa for heating. Calculate the weight of the vapor produced, and the weight of the steam required. Also calculate the necessary heating surface. [Note: The solution is so dilute that its specific heat, latent heat and boiling point may be assumed to be the same as those of water] h= 125.79 kJ/kg, h̟= 419.04 kJ/kg, H,=2676.1 kJ/kg, H,= 2691.5 kJ/kg, h,= 461.30 kJ/kg

Jun 10, 2022
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