b-2. Find the p-value. O pvalue to search

b-2. Find the p-value.<br>O pvalue < 0.01<br>O pvalue 0.10<br>O 0.05 p-value <0.10<br>O 0.025 B p-value <0.05<br>O 0.01B p-value <0.025<br>C. At the 1% significance level, what is the conclusion?<br>O Reject Hg, there is enough evidence to support the claim that the data are not normally distributed.<br>O Do not reject Hg; there is enough evidence to support the claim that the data are not normally distributed.<br>O Do not reject Hg, there is not enough evidence to support the claim that the data are not normally distributed.<br>O Reject Ho, there is not enough evidence to support the claim that the data are not normally distributed.<br>rev: 06 10 2019 QC_CS-170121<br>< Prev.<br>9 of 10<br>Next ><br>to search<br>

Extracted text: b-2. Find the p-value. O pvalue < 0.01="" o="" pvalue="" 0.10="" o="" 0.05="" p-value=""><0.10 o="" 0.025="" b="" p-value=""><0.05 o="" 0.01b="" p-value=""><0.025 c.="" at="" the="" 1%="" significance="" level,="" what="" is="" the="" conclusion?="" o="" reject="" hg,="" there="" is="" enough="" evidence="" to="" support="" the="" claim="" that="" the="" data="" are="" not="" normally="" distributed.="" o="" do="" not="" reject="" hg;="" there="" is="" enough="" evidence="" to="" support="" the="" claim="" that="" the="" data="" are="" not="" normally="" distributed.="" o="" do="" not="" reject="" hg,="" there="" is="" not="" enough="" evidence="" to="" support="" the="" claim="" that="" the="" data="" are="" not="" normally="" distributed.="" o="" reject="" ho,="" there="" is="" not="" enough="" evidence="" to="" support="" the="" claim="" that="" the="" data="" are="" not="" normally="" distributed.="" rev:="" 06="" 10="" 2019="" qc_cs-170121="">< prev.="" 9="" of="" 10="" next=""> to search

Help<br>Consider the following sample data with mean and standard deviation of 17.0 and 7.4, respectively. (You may find it useful to<br>reference the appropriate table: chi-square table or F table)<br>Class<br>Less than 10<br>Frequency<br>36<br>10 up to 20<br>20 up to 30<br>93<br>70<br>30 or more<br>19<br>n = 218<br>a. Using the goodness-of-fit test for normality, specify the competing hypotheses in order to determine whether or not the data are<br>normally distributed.<br>O Ho: The data are normally distributed with a mean of 17.0 and a standard deviation of 7.4.; HA The data are not normally<br>distributed with a mean of 17.0 and a standard deviation of 7.4.<br>O Ho: The data are not normally distributed with a mean of 17.0 and a standard deviation of 74.; HA The data are normally<br>distributed with a mean of 17.0 and a standard deviation of 7.4.<br>b-1. Calculate the value of the test statistic. (Round the z value to 2 decimal places, all other intermediate values to at least 4<br>decimal places and final onswer to 3 decimal places.)<br>Test statistic<br>Prev<br>9 of 10<br>Next ><br>(?<br>中<br>to search<br>

Extracted text: Help Consider the following sample data with mean and standard deviation of 17.0 and 7.4, respectively. (You may find it useful to reference the appropriate table: chi-square table or F table) Class Less than 10 Frequency 36 10 up to 20 20 up to 30 93 70 30 or more 19 n = 218 a. Using the goodness-of-fit test for normality, specify the competing hypotheses in order to determine whether or not the data are normally distributed. O Ho: The data are normally distributed with a mean of 17.0 and a standard deviation of 7.4.; HA The data are not normally distributed with a mean of 17.0 and a standard deviation of 7.4. O Ho: The data are not normally distributed with a mean of 17.0 and a standard deviation of 74.; HA The data are normally distributed with a mean of 17.0 and a standard deviation of 7.4. b-1. Calculate the value of the test statistic. (Round the z value to 2 decimal places, all other intermediate values to at least 4 decimal places and final onswer to 3 decimal places.) Test statistic Prev 9 of 10 Next > (? 中 to search

Jun 07, 2022

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