At the end of a channel is a sharp - edged rectangular weir with a length of 400mm and a coefficient of discharge of 0.65. The water is flowing at a depth of 0.16 m above the crest of the weir. If...


At the end of a channel is a sharp - edged rectangular weir with a length of 400mm and a<br>coefficient of discharge of 0.65. The water is flowing at a depth of 0.16 m above the crest<br>of the weir. If this weir is replaced by a 90 V-notch weir with the same coefficlent of<br>discharge, what will be the necessary upstream depth of water to achieve the same<br>discharge as the rectangular weir. Round off your answer to two decimal places.<br>Use the following equations for discharge<br>Rectangular Weir<br>Q. - CL/2g H/2<br>%3D<br>V-Notch Weir<br>Q. - Ca5 V2g tan<br>15<br>

Extracted text: At the end of a channel is a sharp - edged rectangular weir with a length of 400mm and a coefficient of discharge of 0.65. The water is flowing at a depth of 0.16 m above the crest of the weir. If this weir is replaced by a 90 V-notch weir with the same coefficlent of discharge, what will be the necessary upstream depth of water to achieve the same discharge as the rectangular weir. Round off your answer to two decimal places. Use the following equations for discharge Rectangular Weir Q. - CL/2g H/2 %3D V-Notch Weir Q. - Ca5 V2g tan 15

Jun 11, 2022
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