Assume you now have 1kB of memory, i.e. the memory address space runs from 0 to 1023. The starting address of the first word is 0, the second word is 4, the third word is 8, and so on.
The last word comprising 4 bytes resides in addresses 1020, 1021, 1022, 1023. Thus, the last word starts at 1020, which is a multiple of 4.
Now assume the same 1kB of memory but now, word size is 64 bits. The starting address of the first word is 0, thesecond,third, andlastword starts at?
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