Assume that the number of network errors experienced in a day on a local area network (LAN) is distributed as a Poisson random variable. The mean number of network errors experienced in a day is 2.4....

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Let X be the number of errors in 1 day
X follows Poisson distribution with parameter (rate) λ = 2.4
X ∼ Poisson (λ = 2.4)
A P (X = 0),λ = 2.4
P (X = 0) = e
−λλk
k! =
e−2.4(2.4)0
0! =
(0.090 718) × (1)
1 = 0.090 718
Use excel function POISSON.DIST( X, mean, cumulative) to calculate PX(0):
POISSON.DIST( 0, 2.4, FALSE ) = 0.090 717 953 289 4
P (X = 0) = 0.0907
X
B P (X = 1),λ = 2.4
P (X = 1) = e
−λλk
k! =
e−2.4(2.4)1
1! =
(0.090 718) × (2.4)
1 = 0.217 723
Use excel function POISSON.DIST(...