Assignment of networking and I attached word file

TEMPLATE FOR YOUR ANSWERS
Type your answers in this section in the spaces provided
First Name:_________________________ Last Name:____________________________
Student ID: __________________________
Question Number Mark
allocated
Mark
earned
Question 1: (10 marks)
Routing table of router R2:
Mask Network address Next-hop address Interface
/24 200.11.6.0 ------------------- m1
/22 140.21.0.0 ------------------- m2
/16 150.3.0.0 ------------------- m0
/18 150.32.0.0 150.3.0.1 m1
/24 220.10.40.0 150.3.0.3 m1
/18 161.22.0.0 150.3.0.3 m2
Routing table of router R3:
Mask Network address Next-hop address Interface
/24 200.11.6.0 150.3.0.2 m1
/22 140.21.0.0 150.3.0.2 m2
/16 150.3.0.0 -------------------- m0
/18 150.32.0.0 150.3.0.1 m1
/24 220.10.40.0 --------------------- m1
/18 161.22.0.0 --------------------- m2
10 (5 for
each
table)
Question 2: (6 marks)
a)
Address = 139.145.56.0/22
1
1
st
Address= Address AND Mask
Address = 10001011.10010001.00111000.00000000
Mask = 11111111.11111111.11111100.00000000
First Address= 10001011.10010001.00111000.00000000
= 139.145.56.0
Last Address = Address OR !Mask
! Mask(Binary) = 00000000.00000000.00000011.11111111
Address (Binary) = 10001011.10010001.00111000.00000000
Last Address= 10001011.10010001.00111011.11111111
=139.145.59.255
b) Total Number of Hosts Available in the Network : 1024 Hosts

Department Subnet address Last address Mask
Marketing 139.145.56.0 139.145.56.127 25
Accounting 139.145.57.0 139.145.57.127 25
Head Office 139.145.58.0 139.145.58.63 26
Cust Services 139.145.59.0 139.145.59.15 28

4
c) Unused:
Marketing : 128 -65 =66
Accounting: 128-100=28
Head office 64-33 : 31
Cust Services : 16-13=3
1
Question 3: (4 mark)
a) Data = 5600 -20(IP header)=5580
MTU = 1500-20(IP Header) = 1480
Frag 1: Total Size = 1480 bytes
Starting Byte = 0
Ending Byte = 1479
...