Assignment 2: MARIE and ISAValue:15%Due Date:30-Sep-2018Return Date:18-Oct-2018Length:Submission...

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Assignment 2: MARIE and ISAValue:15%Due Date:30-Sep-2018Return Date:18-Oct-2018Length:Submission method options:Alternative submission methodTask	back to topQuestion 1:A digital computer has a memory unit with 16 bits per word. The instruction set consists of 122 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory. [10 marks]	How many bits are needed for the opcode?		How many bits are left for the address part of the instruction?	What is the maximum allowable size for memory?	What is the largest unsigned binary number that can be accommodated in one word of memory?	Question 2:Consider an instructionAdd 1000. Memory contents, Accumulator (AC), and R1 Register contents are depicted in the below figure: (such as memory address 1000 contains a value 1400, memory address 1100 contains a value 400 etc. All the numbers used here are decimals.) [8 marks]	Assuming R1 is implied in the indexed addressing mode, determine the actual value loaded into the accumulator (AC) using the following addressing modes:	Immediate	Direct	Indirect	Indexed	Question 3:More registers appears to be a good thing, in terms of reducing the total number of memory accesses a program might require. Using the arithmetic expression S = (A+B)-(C+D), support this statement. [Hints: First, determine the number of memory accesses necessary using MARIE and the two registers for holding memory data values (AC and MBR). Then perform the same arithmetic computation for a processor that has more than three registers (for example, R1, R2, R3, R4) to hold memory data values.][6 marks]	Question 4:Assemble the MARIE program below.[6 marks]	Hex Address  Label Instruction100         Start  LOAD A101               ADD B102               STORE D103               CLEAR104               OUTPUT105               ADDI D106               STORE B107               HALT108         A,    HEX 00FC109         B,    DEC 1410A        C,     HEX 010810B         D,    HEX 0000	a) List the hexadecimal code for each instruction [2 marks]b) Draw the symbol table [2 marks]c) What is the value stored in the AC when the program terminates? [2 marks]Rationale

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Assignment 2: MARIE and ISA
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Table of Contents
a)	Answer 1	3
b)	Answer 2	4
c)	Answer 3	5
d)	Answer 4	6
e)	References:	8
a) Answer 1
1)  
The executed instructions are indicated by an opcode. As it is given 
Executed instructions =  
Binary conversion of  =  
From above, 7 bits are defining the operations of  instructions. Thus,  bits will be required to opcode. 
2)  
Assume that  bits/word are used by memory and from calculation of part 1,  bits are required for opcode, so, 
Number of address bits = total bits/word – number of opcode bits
 
So, 9 bits are left for address part. 
3)  
From calculation of part 2,  bits are left for address part and we know that
 
So,
Thus, maximum size for 16 bit requires .
4)  
From calculations of part 3, Number of word in memory  
So,
And unsigned number range is from . 
So,
So; one word memory will accommodate as the largest unsigned binary number. 
b) Answer 2
The used addressing modes are listed below: 
1) 
Immediate:  
So, 
 
2) 
Direct:  
So, 
 
3) 
Indirect :  
So, 
 
4) 
Indexed:  
So,

Assignment 2: MARIE and ISA Value: 15% Due Date: 30-Sep-2018 Return Date: 18-Oct-2018 Length: Submission method options: Alternative submission method Task back to top Question 1: A digital computer...

Assignment 2: MARIE and ISA

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Answer To: Assignment 2: MARIE and ISA Value: 15% Due Date: 30-Sep-2018 Return Date: 18-Oct-2018 Length:...

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