Assignment 2: MARIE and ISA Value: 15% Due Date: 30-Sep-2018 Return Date: 18-Oct-2018 Length: Submission method options: Alternative submission method Task back to top Question 1: A digital computer...

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Answer To: Assignment 2: MARIE and ISA Value: 15% Due Date: 30-Sep-2018 Return Date: 18-Oct-2018 Length:...

Amit answered on Sep 29 2020
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Assignment 2: M
ARIE and ISA
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Table of Contents
a)    Answer 1    3
b)    Answer 2    4
c)    Answer 3    5
d)    Answer 4    6
e)    References:    8
a) Answer 1
1)
The executed instructions are indicated by an opcode. As it is given
Executed instructions =
Binary conversion of =
From above, 7 bits are defining the operations of instructions. Thus, bits will be required to opcode.
2)
Assume that bits/word are used by memory and from calculation of part 1, bits are required for opcode, so,
Number of address bits = total bits/word – number of opcode bits

So, 9 bits are left for address part.
3)
From calculation of part 2, bits are left for address part and we know that

So,
Thus, maximum size for 16 bit requires .
4)
From calculations of part 3, Number of word in memory
So,
And unsigned number range is from .
So,
So; one word memory will accommodate as the largest unsigned binary number.
b) Answer 2
The used addressing modes are listed below:
1)
Immediate:
So,

2)
Direct:
So,

3)
Indirect :
So,

4)
Indexed:
So,

c) Answer 3
The given...
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