Assestment I 1. The domain of f(x) = .,112,c2 in interval notation is: a. [41,11] b. (0, ) c. (11, ) d. (-11,11) 2. Given f(x) = 6—x and g(x) = 2x2+x, find (g0 f)(-2) a. -4 b. 0 c. 36 d. 136 3. Write...

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Assestment I
1. The domain of f(x) = .,112,c2 in interval notation is: a. [41,11] b. (0, ) c. (11, ) d. (-11,11)
2. Given f(x) = 6—x and g(x) = 2x2+x, find (g0 f)(-2) a. -4 b. 0 c. 36 d. 136
3. Write an equation for a function that has a graph with the given characteristics. The shape of x2, but upside down and shifted right 5 units. a. y = —x2-5 b. y = —(x-5)2 c. y = —(x+5)2 d. y = —x2+5
4. Express In(.1875) in terms of In(2) and In(3). a. -41n(2) + In(3) b. In(3/16) c. -In(3) + 41n(2) d. none of these
5. Use a reference triangle to find tan-1(-4T). a. —27—t- / 3 b. —,r/3 c. 2-c/3 d. 2,r/3



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Answered Same DayDec 29, 2021

Answer To: Assestment I 1. The domain of f(x) = .,112,c2 in interval notation is: a. [41,11] b. (0, ) c. (11, )...

David answered on Dec 29 2021
129 Votes
Solution
Solutions ARE HIGHLIGHTED
Now square root exist only for positive numbers and hence function
inside the square root must be positive
So
121-x2 >=0
x2 <= 121
x [-11,11]
option A
Gof(x) =
replace x by f(x) in g(x)
So gof(x) = 2* f(x)2 +f(x)
Putting -2
F(-2)= 6—2 = 8
Hence gof(-2) = 2*64+8 = 136
Option D
Upside down so and shape of x^2
Y= -(x-a)2
Shifted right 5 unit so Y is zero when x= 5
Hence Y= -(x-5)2
And Option B
Ln(0.1875)
.1875 = 1875/10000 = 25*25*3/25*25*16= 3/16
Ln(3/16)= ln3 -ln 16 = ln 3- 4ln2
Hence option A
tan(60)= sqrt(3)
hence angle is – 60
option B
Take 1998 as base ear
Let Population = C*exp(at)
C= 1225
At t=5 after 5 year population is 2340
C*exp(5a)= 2340
Exp(5a)= 2340/1225, a=0.1294
Population in 2008
C*exp(10a)= 1225 *exp(10a)= 4470
Hence correct option B
Rate of change = 12x^2
Average of rate of change=
6
2
4
3 6
4
[ 12 ] / 2
[4 ] / 2 608 / 2 304
x dx
x  

Hence Option C
Option D does not exists
Using L hospital rule and differentiating both numerator and
denomerator we get
0
0
0
2 1 1
2
2 2 1
1
1
1
2 1
x
x
x
x
Lim
x
x
Lim
Lim
x



 



Option B
Take a=sqrt(9theta)
Now when theta tends to zero a also tends to zero
And hence it is reduced to
0
9sin( )
9a
a
Lim
a
  Hence correct option D
Dividing numerator and denominator by x^5 we gwt
4 / 7 / ^ 2 4 / ^ 5
0
7
x
x x x
Lim 
 

Hence as x tends to infinity 1/x tends to zero
So correct option is A
This function has only a vertical asymptote at x=2
Hence option D
Slope dy/dx= -12x = -60
Hence line is y= -60x +c
Putting point (5,-147) we get c= 153
Hence correct option is D
Velocity = -gt= -9.8*5 = -49
But speed is not a vector quantity and it is always positive
Hence correct option is C
F(x+h)= 3-(x+h)^2 = 3-x^2-2xh-h^2
Hence correct option is D
For f= x^n
Df/dx = nx^n-1
Using same formula dy/dx = -24x^3-14x
Hence correct option is A
Using differentiation rule for fraction
Which is
2
2
2
( )* * ( )
4(3 2) 3(4...
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