Test for the fourth week Document: Assessment Task Hypothesis_Regression_Time series index numbers sem2-18.doc Page 1 of 5 Assessment task for Hypothesis, Regression Time series/ Index Numbers sem...

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Answered Same DayOct 11, 2020ECON1248

Answer To: Test for the fourth week Document: Assessment Task Hypothesis_Regression_Time series index numbers...

Pooja answered on Oct 12 2020
143 Votes
Initialization:
    My Student ID
    3533069
    A
    35
    B
    69
    C
    33
    D
    30
    E
    36
    F
    (13, 15, 13, 13, 10, 16, 19, 23)
1)

Step 1:
ho: orders are taking equal to 10 minutes. u = 10
h1: orders are taking longer than 10 minutes. u>10
Step 2:
Alpha = 1%
Step 3:
mean=     10.90
sd= sqrt(var)     0.88
u=     10.00
n=     69.00
test statistic, z = (mean-u)/(sd/sqrt(n))
= (10.9-10)/(0.875/sqrt(69))
8.544
Step 4:
Critical value, z(a)
z(0.01)
2.326
1-P(Z1-P(z<8.544)
=1-NORMSDIST(8.544)
0.0000
Step 5:
The decision rule is to reject Ho if z > z(a) or p-value <1%
Step 6:
With z=8.544 and p<1%, I reject Ho at 1% level of significance and conclude that orders are taking longer than 10 minutes. u>10
2)
1)
Step 1:
ho: The proportion of people who love dogs is 75 % Australia wide. p = .75
h1: The proportion of people who love dogs is not 75 % Australia wide. p =/= .75
Step 2:
Alpha = 5%
Step 3:
n=    33
p = X/n=     0.680
po=     0.750
test statistic, z = (phat-p)/sqrt(p*(1-p)/n)
=(0.68-0.75)/SQRT(0.75*(1-0.75)/33)
-0.92866
Step 4:
P-value
2*(1-P(z<|z|)
2*(1-P(znormsdist(abs(-0.928655))
0.3531
Step 5:
The decision rule is to reject Ho p-value <5%
Step 6:
With z=-0.92866 and p>5%, I fail to reject Ho at 5% level of significance and...
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