Apply the concept of ac signals to Figure 1, the value of current across XL2 is * 3.2000 - 2.4000i 3.2000 + 2.4000i O -3.2000 - 2.4000i -3.2000 + 2.4000i Apply the concept of ac signals to Figure 2,...


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Apply the concept of ac signals<br>to Figure 1, the value of current<br>across XL2 is *<br>3.2000 - 2.4000i<br>3.2000 + 2.4000i<br>O -3.2000 - 2.4000i<br>-3.2000 + 2.4000i<br>Apply the concept of ac signals<br>to Figure 2, the value of voltage<br>drop across XC1 is *<br>50 + 50i<br>50 - 50i<br>-50 + 50i<br>-50 - 50i<br>

Extracted text: Apply the concept of ac signals to Figure 1, the value of current across XL2 is * 3.2000 - 2.4000i 3.2000 + 2.4000i O -3.2000 - 2.4000i -3.2000 + 2.4000i Apply the concept of ac signals to Figure 2, the value of voltage drop across XC1 is * 50 + 50i 50 - 50i -50 + 50i -50 - 50i
+ V2-<br>R = 82<br>R, = 82<br>1 = SA 20°<br>ll<br>X, = 30<br>Figure 1<br>R-<br>560 1<br>R 200 2<br>E = 100 V 20<br>560 2<br>= 400 :<br>XG, = 400 2<br>Figure 2<br>000<br>

Extracted text: + V2- R = 82 R, = 82 1 = SA 20° ll X, = 30 Figure 1 R- 560 1 R 200 2 E = 100 V 20 560 2 = 400 : XG, = 400 2 Figure 2 000

Jun 10, 2022
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