Analysis of PrefixAverages2 cost c, Create an array A such that length[A] = length[X] C2 S- 0 C3 for j+ 1 to length[X] C4 do s+s + X[j] C5 A[j] +s/j C6 return A Mini-Homework 1 (due next class) 1....

Analysis of PrefixAverages2<br>cost<br>c, Create an array A such that length[A] = length[X]<br>C2 S- 0<br>C3 for j+ 1 to length[X]<br>C4 do s+s + X[j]<br>C5<br>A[j] +s/j<br>C6 return A<br>Mini-Homework 1 (due next class)<br>1. T(n) = ??<br>2. Is there a difference in T(n) for best and worst case input?<br>

Extracted text: Analysis of PrefixAverages2 cost c, Create an array A such that length[A] = length[X] C2 S- 0 C3 for j+ 1 to length[X] C4 do s+s + X[j] C5 A[j] +s/j C6 return A Mini-Homework 1 (due next class) 1. T(n) = ?? 2. Is there a difference in T(n) for best and worst case input?

Jun 10, 2022

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Analysis of PrefixAverages2 cost c, Create an array A such that length[A] = length[X] C2 S- 0 C3 for j+ 1 to length[X] C4 do s+s + X[j] C5 A[j] +s/j C6 return A Mini-Homework 1 (due next class) 1....

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