An egg distributer determines that the probability that any individual egg has a crack is 0.17. a) Write the binomial probability formula to determine the probability that exactly x eggs of n eggs are...

(See attached image - choose the correct answer below for part a & b)


Extracted text: An egg distributer determines that the probability that any individual egg has a crack is 0.17. a) Write the binomial probability formula to determine the probability that exactly x eggs of n eggs are cracked. b) Write the binomial probability formula to determine the probability that exactly 3 eggs in a one-dozen egg carton are cracked. Do not evaluate. a) Choose the correct answer below. O A. P(x) =,C(0.83) (0.17)-x O B. P(x) =,C(0.17)* (0.83)" -x OC. P(x)=,C,(0.17)* (0.83) -x O D. P(x) =,C(0.83)* (0.17)" -x b) Choose the correct answer below. O A. P(x) =3C12(0.83) (0.17)9 O B. P(x) =3C12(0.17) (0.83)° OC. P(x) = 12C3(0.17) (0.83)° O D. P(x) = 12C3(0.83) (0.17)° Click to select your answer. Next