An automotive company measured the position of a test car during a 50 second time period during two trial test runs. Trial 1 Trial 2 Time (T) [sec] 20 Position (P) Position (P) [m] [m] 1439 984 25...

Extracted text: An automotive company measured the position of a test car during a 50 second time period during two trial test runs. Trial 1 Trial 2 Time (T) [sec] 20 Position (P) Position (P) [m] [m] 1439 984 25 1791 824 30 2059 1164 35 1564 1396 40 1930 1844 45 2569 2298 50 2308 1691 55 3241 2358 60 3238 2389 65 3952 2691 70 3635 2478 We are interested in obtaining the linear relationship between the time (T) and position (P). During Trial 1, analysis showed the automobile position followed the relationship P = 48.9*T + 320 You are expected to develop a similar relationship for Trial 2. You should consider time as the independent variable X, and position as the dependent variable Y. a) Calculate E X;. b) Calculate E Y;. c) Calculate EX;X¡. d) Calculate E Y,Y;. e) Calculate Σ Χ.,Y, f) Using the least squares approach, calculate the slope m and y-intercept b for the straight line which best fits the data for Trial 2. You may NOT use Excel. g) Calculate the coefficient of correlation, r, for the line found in step f. You may NOT use Excel. h) Plot both Trial 1 and Trial 2 data found in the table along with the trend line evaluated in step f. You may present the plot using Excel output. i) Which Trial had the highest average velocity for the duration of the test run? How did you determine your answer?