According to an Automobile Association of America report, 9.6% of Americans traveled by car over the 2011 Memorial Day weekend and 88.09% stayed home. What is the probability that a randomly selected...


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According to an Automobile Association of America report, 9.6% of Americans traveled by car over the 2011 Memorial Day<br>weekend and 88.09% stayed home.<br>What is the probability that a randomly selected American stayed home or traveled by car over the 2011 Memorial Day weekend?<br>P(stayed home or travelled by car)= i<br>Explain why this probability does not equal 1.0.<br>This probability is not equal to 1.0 because<br>

Extracted text: According to an Automobile Association of America report, 9.6% of Americans traveled by car over the 2011 Memorial Day weekend and 88.09% stayed home. What is the probability that a randomly selected American stayed home or traveled by car over the 2011 Memorial Day weekend? P(stayed home or travelled by car)= i Explain why this probability does not equal 1.0. This probability is not equal to 1.0 because

Jun 06, 2022
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