According to a recent survey, Americans were expected to spend an average of 985.50 hours watching television in 2019. Suppose that the standard deviation of the distribution of times that Americans...


According to a recent survey, Americans were expected to spend an average of 985.50 hours watching television in 2019. Suppose<br>that the standard deviation of the distribution of times that Americans spent watching television in 2019 is 285.20 hours.<br>Using Chebyshev's theorem, find the interval that will contain the television viewing times of at least 75% of all Americans.<br>Enter the exact answers.<br>From<br>hours to<br>hours.<br>

Extracted text: According to a recent survey, Americans were expected to spend an average of 985.50 hours watching television in 2019. Suppose that the standard deviation of the distribution of times that Americans spent watching television in 2019 is 285.20 hours. Using Chebyshev's theorem, find the interval that will contain the television viewing times of at least 75% of all Americans. Enter the exact answers. From hours to hours.

Jun 11, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here