A1 fe ANOVA A. B E F G 1 ANOVA 2 df Significance F MS 3 Regression 4 Residual 5 Total 1 1575.76 8 349.14 1924.90 6 7 Coefficients Standard Error t Stat P-value 8 Intercept 6.1092 0.9361 9 Usage 0.8951...


A1<br>fe<br>ANOVA<br>A.<br>B<br>E<br>F<br>G<br>1 ANOVA<br>2<br>df<br>Significance F<br>MS<br>3 Regression<br>4 Residual<br>5 Total<br>1<br>1575.76<br>8<br>349.14<br>1924.90<br>6<br>7<br>Coefficients<br>Standard Error<br>t Stat<br>P-value<br>8 Intercept<br>6.1092<br>0.9361<br>9 Usage<br>0.8951<br>0.149<br>10<br>11<br>12<br>13<br>14<br>15<br>16<br>17<br>18<br>19<br>

Extracted text: A1 fe ANOVA A. B E F G 1 ANOVA 2 df Significance F MS 3 Regression 4 Residual 5 Total 1 1575.76 8 349.14 1924.90 6 7 Coefficients Standard Error t Stat P-value 8 Intercept 6.1092 0.9361 9 Usage 0.8951 0.149 10 11 12 13 14 15 16 17 18 19
Following is a portion of the regression output for an application relating maintenance expense (dollars per month) to usage (hours per week) for a particular brand of computer terminal.<br>Excel File: data14-41.xlsx<br>ANOVA<br>df<br>Ss<br>MS<br>F<br>Significance F<br>Regression<br>1.<br>1575.76<br>Residual<br>8<br>349.14<br>Total<br>1924.90<br>Coefficients Standard Error<br>t Stat<br>P-value<br>Intercept<br>6.1092<br>0.9361<br>Usage<br>0.8951<br>0.149<br>If your answer is zero, enter

Extracted text: Following is a portion of the regression output for an application relating maintenance expense (dollars per month) to usage (hours per week) for a particular brand of computer terminal. Excel File: data14-41.xlsx ANOVA df Ss MS F Significance F Regression 1. 1575.76 Residual 8 349.14 Total 1924.90 Coefficients Standard Error t Stat P-value Intercept 6.1092 0.9361 Usage 0.8951 0.149 If your answer is zero, enter "0". a. Write the estimated regression equation (to 4 decimals). b. Use a t test to determine whether monthly maintenance expense is related to usage at the 0.05 level of significance (to 2 decimals). Use Table 2 of Appendix B. t = p-value = Reject v the null hypothesis. Monthly maintenance expense is not v related to usage. c. Did the estimated regression equation provide a good fit? Explain. Hint: If p2 is greater than 0.50, the estimated regression equation provides a good fit. , because the value of pl is less v than 0.50. No

Jun 09, 2022
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