A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes...

I need help solving this in JAVA

Extracted text: A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 leap year | Ex: If the input is: 1913 the output is: 1913 not a leар уear 373020.2041158.gx3zqy7


Extracted text: 1 import java.util.Scanner; 2 3 public class LabProgram { public static void main(String args) { Scanner scnr = new Scanner(System.in); int inputYear; boolean isLeapYear; 4. %3D 6. 8. 9. isLeapYear = false; inputYear = scnr.nextInt(); %3D 10 %3D 11 12 /* Type your code here. */ 13 14 } 15