A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes...


I am lost on how to use the "if_name_=='_main_':" to solve this problem. I'm stuck after line 10.


A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around<br>the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year<br>has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:<br>1) The year must be divisible by 4<br>2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400<br>Some example leap years are 1600, 1712, and 2016.<br>Write a function is_leap_year that will return True if the year is a leap year and False otherwise.<br>Write a program that takes in a year, uses the function to determine whether that year is a leap year, and prints<br>the response, like given below.<br>Ex: If the input is:<br>1712<br>the output is:<br>1712 is a leap year.<br>Ex: If the input is:<br>1913<br>the output is:<br>1913 is not a leap year.<br>Your program must define and call the following function. The function should return True if the input year is a<br>leap year or False otherwise.<br>def is_leap_year(user_year)<br>Troubleshooting<br>If your function is failing the tests and is saying that it

Extracted text: A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a function is_leap_year that will return True if the year is a leap year and False otherwise. Write a program that takes in a year, uses the function to determine whether that year is a leap year, and prints the response, like given below. Ex: If the input is: 1712 the output is: 1712 is a leap year. Ex: If the input is: 1913 the output is: 1913 is not a leap year. Your program must define and call the following function. The function should return True if the input year is a leap year or False otherwise. def is_leap_year(user_year) Troubleshooting If your function is failing the tests and is saying that it "did not return a value. Your function may be missing a return statement", then go back to the lab instructions and check -- what is the function supposed to return and under which conditions. Note that your code can have more than one return statement in it, since you might need to return different values, depending on the condition.
1 # Define your function here.<br>2 def is_leap_year (user_year):<br>if (year%400==0):<br>3<br>4<br>return True<br>elif year % 100 == 0:<br>return False<br>7<br>elif year%4==0:<br>8<br>return True<br>else:<br>10<br>return False<br>11<br>12 if<br>== ' _main_':<br>name<br>13<br>14<br># Type your code here. Your code must call the function.<br>

Extracted text: 1 # Define your function here. 2 def is_leap_year (user_year): if (year%400==0): 3 4 return True elif year % 100 == 0: return False 7 elif year%4==0: 8 return True else: 10 return False 11 12 if == ' _main_': name 13 14 # Type your code here. Your code must call the function.
Jun 04, 2022
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