A vapor mixture of n-butane and n-hexane contains 50.0 mol % butane at 120°C and 1.0 atm. A stream of this mixture flowing at a rate of 150.0 L/s is cooled and compressed, causing some but not all of...

Extracted text: A vapor mixture of n-butane and n-hexane contains 50.0 mol % butane at 120°C and 1.0 atm. A stream of this mixture flowing at a rate of 150.0 L/s is cooled and compressed, causing some but not all of the vapor to condense. Liquid and vapor product streams emerge from the process in equilibrium at T and 1100 mm Hg. The vapor product contains 60.0 mol % butane. Determine the required final temperature, and composition of the liquid product (in mole fractions. Use the following: log P |mmHg |- A- T°C]+ C For Butane: A = 6.52485, B = 943.453, C = 239.711 For Hexane: A = 6.88555, B = 1175.817, C = 224.867